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OLEGan [10]
3 years ago
10

If the hot dog eating champion's goal is to eat 1 hot dog every 13 seconds, how many whole hot dogs does he expect to eat in 12

minutes?
Mathematics
1 answer:
sweet [91]3 years ago
6 0
He wil eat a total of 55.2 hot  dogs. there 60 seconds in a minute . he plans to eat 1 hotdog in every  13 seconds . you divide 60 by 13 . he will eat 4.6 hot dogs in  a minute . then you multiply 4.6 by 12.
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Is 27 prime or composite?
marysya [2.9K]

Answer: It is not prime , therefor it's composite.

Step-by-step explanation:

Because....

The number 27 can be evenly divided by 1, 3, 9 and 27, with no remainder.

* Hopefully this helps:) Mark me the brainliest:)!!!

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What is the solution to the system of equations?
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Hello, I just want to say thank you so much to brainly! :)
Volgvan

Answer:

I totally agree

Step-by-step explanation:

It helps a lot.

4 0
3 years ago
A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

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saw5 [17]

Answer:

B) X = 90

Step-by-step explanation:

If you plug in every answer choice as "X," you can easily find which answer helps the equation equal 40.

EX. 1/2 (or 0.50) times 90 plus -4 equals 41!

Equation with "X" filled in as 90 :

41 = 1/2 x 90 + (-4)!!!

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