2 years ago

The tables below show the values of f(x) and g(x) for different values of x:

Mathematics

2 answers:

morpeh [17]2 years ago

6 0

The answer is c I think

svet-max [94.6K]2 years ago

6 0

C!!!!!!!!!!!!!!! at least i think

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Simplify 22-5(2x+4)<br> a. -10x+26<br> b. -10x+2<br> c. 34x+4<br> d. 34x+68

KengaRu [80]

Hi.

$22-5(2x+4) \\ \\ \implies 22-10x-20 \\ \\ \implies -10x+22-20 \\ \\ \implies -10x +2$

Hence,

The correct option is $\boxed{\sf b. -10x+2}$

Thanks.

7 0

3 years ago

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HELP NOW I NEED IT AND IS DUE TODAY

Mnenie [13.5K]

D and E because they are both colder than -10

3 0

2 years ago

43.586 rounded to the nearest hundredth

garik1379 [7]

So you round to the second decimal place, giving you 43.59

3 0

3 years ago

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Evaluate the function ƒ( x ) = x 2 + 1 for ƒ(2).

Andrews [41]

Is that x squared? Cause if so then the answer would be f= 5

7 0

2 years ago

Use the data in the table to answer the question. Citations are "speeding tickets." You may fill in the table to help you answer

Vikentia [17]

Answer:

Linear approximation is given by: $y = \frac{x}{5}+2$

Step-by-step explanation:

We are given the following information in the question:

Number of citations: 5 7.5 10 15 20

Outputs Residuals: 3 6 10 5 6

We have to find the linear approximation of the data that passes through the points (5, 3) and (20, 6).

Linear approximation is given by:

The equation of line is given by:

$(y-y_1) = \displaystyle\frac{y_2-y_2}{x_2-x_1}(x-x_1)$

where, $(x_1,y_1), (x_2.y_2)$ is the point through which the line passes.

The equation of line is:

$(y-3) = \displaystyle\frac{6-3}{20-5}(x-5)\\\\15(y-3)= 3(x-5)\\15y = 3x-15+45\\15y = 3x + 30\\y = \frac{x}{5}+2$

The above equation is the required linear approximation.

8 0

3 years ago