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3 years ago

Study the equation below 25= 2x + 3

1 answer:

3 0

Let's solve 'em all!

Original Equation:
25 = 2x + 3
-3 -3
22 = 2x
/2 /2
11 = x (So now we are looking for an equation that has the solution: 11)

A.
28 = 2x
/2 /2
14 = x

B
22 = 2x
/2 /2
11 = x

C
50 = x + 3
-3 -3
47 = x

D
25/2 = x + 3
12.5 = x + 3
-3 -3
9.5 = x

Thus, the answer is B since both 25 = 2x + 3 and 22 = 2x both are equivalent to 11.

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The y -intercept is often referred to with just the y -value.

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2 years ago

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3 years ago

3 times (-8) times (-2)

dexar [7]

Answer:

Step-by-step explanation:

Signals during a multiplication of two numbers:

They have the same signal: The multiplication is positive.

They have different signals: The multiplication is negative.

3 times (-8) times (-2)

First 3*(-8):

Different signals, so negative. 3*8 = 24. So the answer is -24.

Then:

3*(-8)*(-2) = (-24)*(-2)

Same signal, so positive. 24*2 = 48. The answer is 48.

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1 year ago

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3 years ago

A line for tickets to a Broadway show had a mean waiting time of 20 minutes with a standard deviation of 5 minutes.

andrezito [222]

Answer:

5.48% of the people in line waited for more than 28 minutes

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean waiting time of 20 minutes with a standard deviation of 5 minutes.

This means that $\mu = 20, \sigma = 5$

What percentage of the people in line waited for more than 28 minutes?

The proportion is 1 subtracted by the p-value of Z when X = 28. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{28 - 20}{5}$

$Z = 1.6$

$Z = 1.6$ has a p-value of 0.9452.

1 - 0.9452 = 0.0548.

As a percentage:

0.0548*100% = 5.48%

5.48% of the people in line waited for more than 28 minutes

6 0

2 years ago