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3 years ago

Can someone help me please

Mathematics

2 answers:

kramer3 years ago

8 0

Answer:

Loading...

Step-by-step explanation:

Ludmilka [50]3 years ago

4 0

Answer:

IJ = 15

Step-by-step explanation:

Since ∠ I ≅ ∠ H , then Δ HIJ is isosceles with sides JH and IJ congruent.

Thus IJ = JH = 15

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<h3><u>Solution:- </u></h3>

Let the number to be added be A

Now,

$\begin{gathered}\implies\quad \sf −5x^3 + 4x − 3 + A = x^2 − x − 1 \\\end{gathered}$

Transposing (−5x³+ 4x − 3 ) to other side-

$\begin{gathered}\\\implies\quad \sf A = x^2 − x − 1 -( −5x^3 + 4x − 3) \\\end{gathered}$

Remember if there is a -ve sign before a bracket the signs of whole of the terms changes on opening bracket

$\begin{gathered}\\\implies\quad \sf A = x^2 − x − 1 + 5x^3 - 4x + 3\\\end{gathered}$

Putting like terms together -

$\begin{gathered}\\\implies\quad \sf A = 5x^3 +x^2 - x -4x +3 -1 \\\end{gathered}$

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