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yulyashka [42]
3 years ago
8

Theo can paint a fence three times as fast as his sister can. Working together, they can paint a fence in 9 hours. How many hour

s would it take Theo’s sister to paint the fence by herself?
Mathematics
1 answer:
Deffense [45]3 years ago
8 0

Answer:

12 hours

Step-by-step explanation:

Let Theo's siste can paint a fence in x times

Given.

Theo can paint a fence three times as fast as his sister can. Working together, they can paint a fence in 9 hours.

\frac{1}{x}+\frac{1}{3x} =\frac{1}{9}\\\frac{3+1}{3x} =\frac{1}{9} \\\frac{4}{3x}=\frac{1}{9}

Apply cross multiplication

x=\frac{9\times 4}{3}\\x=\frac{36}{3} \\x=12hours

Theo’s sister to paint the fence in 12 hours.

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PLEASE HELP GIVING MANY POINTS!
NeTakaya

Answer:

  69.01 m

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you ...

  Tan = Opposite/Adjacent

The tangent function is useful for problems like this. Let the height of the spire be represented by h. The distance (d) across the plaza from the first surveyor satisfies the relation ...

  tan(50°) = (h -1.65)/d

Rearranging to solve for d, we have ...

  d = (h -1.65)/tan(50°)

The distance across the plaza from the second surveyor satisfies the relation ...

  tan(30°) = (101.65 -h)/d

Rearranging this, we have ...

  d = (101.65 -h)/tan(30°)

Equating these expressions for d, we can solve for h.

  (h -1.65)/tan(50°) = (101.65 -h)/tan(30°)

  h(1/tan(50°) +1/tan(30°)) = 101.65/tan(30°) +1.65/tan(50°)

We can divide by the coefficient of h and simplify to get ...

  h = (101.65·tan(50°) +1.65·tan(30°))/(tan(30°) +tan(50°))

  h ≈ 69.0148 ≈ 69.01 . . . . meters

The tip of the spire is 69.01 m above the plaza.

3 0
3 years ago
If f(x) = x^2 - 2x and g(x) = 6x + 4, for what value of x does (f + g)(x) = 0?
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Answer:

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Step-by-step explanation:

f(x) =x^2 -2x\:\: and \:\: g(x) = 6x + 4\\(f+g)(x) = f(x) + g(x) \\(f+g)(x) = x^2 -2x+ 6x + 4\\(f+g)(x) = x^2+4x + 4\\(f+g)(x) = (x+2)^2\\ 0 = (x+2)^2...[\because (f+g)(x) =0]\\0 = x+2\\\therefore x = -2

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Answer:

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