Its all up to you and how hard you are willing to work to get that may credits in one semester. But you could do it. Hope that helped!
The radius of the circle would be 10.19 I hope this helped!! :)
we can see that the center is (-3, 3) and the radius is 9 units.
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How to find the center and radius of the circle?</h3>
The general circle equation, for a circle with a center (a, b) and radius R is given by:
(x - a)^2 + (y - b)^2 = R^2
Here we have the equation:
x^2 + y^2 + 6x = 6y + 63
Let's complete squares:
x^2 + y^2 + 6x - 6y = 63
(x^2 + 6x) + (y^2 - 6y) = 63
(x^2 + 2*3x) + (y^2 - 2*3y) = 63
Now we can add and subtract 9, (two times) so we get:
(x^2 + 2*3x + 9) - 9 + (x^2 - 2*3x + 9) - 9 = 63
(x + 3)^2 + (y - 3)^2 = 63 + 9 + 9 = 81 = 9^2
(x + 3)^2 + (y - 3)^2 = 9^2
Comparing with the general circle equation, we can see that the center is (-3, 3) and the radius is 9 units.
If you want to learn more about circles:
brainly.com/question/1559324
#SPJ1
The list of choices you included doesn't have any correct expressions on it.
-- If the rocket went straight up, and then dropped back at the same place
it was launched from, then it must have dropped straight down.
-- The route it followed on the way down was exactly the same as the
route it followed on the way up.
-- Since it reached a maximum height of 150-ft from the ground
and the route was straight, the length of the route was 150-ft.
-- (150-ft going up) plus (150-ft coming down) = 300-ft traveled all together.
