Answer:
A
Step-by-step explanation:
![cos~ \theta=\sqrt{1-sin^2 \theta} =\sqrt{1-(\frac{1}{2})^2 } =\frac{\sqrt{3} }{2} \\1+cos~\theta=2cos^2\frac{\theta}{2} \\1+\frac{\sqrt{3}}{2} =2~cos^2 \frac{\theta}{2} \\cos^2\frac{\theta}{2} =\frac{2+\sqrt{3}}{2 \times 2} \\cos \frac{\theta}{2} =\frac{\sqrt{2+\sqrt{3}}}{2} \\1-cos \theta=2 ~sin^2\frac{\theta}{2} \\1-\frac{\sqrt{3}}{2}=2~sin^2 \frac{\theta}{2} \\sin^2 \frac{\theta}{2} =\frac{2-\sqrt{3} }{2 \times 2} \\sin \frac{\theta}{2}=\frac{\sqrt{2-\sqrt{3} } }{2}](https://tex.z-dn.net/?f=cos~%20%5Ctheta%3D%5Csqrt%7B1-sin%5E2%20%5Ctheta%7D%20%3D%5Csqrt%7B1-%28%5Cfrac%7B1%7D%7B2%7D%29%5E2%20%7D%20%3D%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D%20%5C%5C1%2Bcos~%5Ctheta%3D2cos%5E2%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%5C%5C1%2B%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%20%3D2~cos%5E2%20%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%5C%5Ccos%5E2%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%3D%5Cfrac%7B2%2B%5Csqrt%7B3%7D%7D%7B2%20%5Ctimes%202%7D%20%5C%5Ccos%20%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%3D%5Cfrac%7B%5Csqrt%7B2%2B%5Csqrt%7B3%7D%7D%7D%7B2%7D%20%5C%5C1-cos%20%5Ctheta%3D2%20~sin%5E2%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%5C%5C1-%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%3D2~sin%5E2%20%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%5C%5Csin%5E2%20%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%3D%5Cfrac%7B2-%5Csqrt%7B3%7D%20%7D%7B2%20%5Ctimes%202%7D%20%5C%5Csin%20%5Cfrac%7B%5Ctheta%7D%7B2%7D%3D%5Cfrac%7B%5Csqrt%7B2-%5Csqrt%7B3%7D%20%7D%20%7D%7B2%7D)
as 0≤θ≤90
so θ/2 is also in 0≤θ≤90
hence sin θ/2 and cos θ/2 are positive.
The domain of a graph is all of the x-values of the graph. Since the graph looks like it continues and never ends, every single x value is included in the domain, thereby making all reals the correct answer
Answer:
It's 3/40
Step-by-step explanation:
In order for the expression to equal 10 you have to turn it into this (all numbers are still doing the same action):
6×2-(5-3)
solve it:
6×2-(5-3)
12-(5-3)
12-2
10
Hope I helped...
5 rotten potatoes is = 1.43125 kg