Answer and Explanation:
Given : Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder.
To find :
a. Does the table show a probability distribution?
b. Find the mean and standard deviation of the random variable x.
Solution :
a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.


Yes it is a probability distribution.
b) First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.029 0 0 0
1 0.147 0.147 1 0.147
2 0.324 0.648 4 1.296
3 0.324 0.972 9 2.916
4 0.147 0.588 16 2.352
5 0.029 0.145 25 0.725
∑P(x)=1 ∑xP(x)=2.5 ∑x²P(x)=7.436
The mean of the random variable is

The standard deviation of the random sample is







Therefore, The mean is 2.5 and the standard deviation is 1.08.
Answer:
Graph
Step-by-step explanation:
The graph swapped the y and x axis values.
Answer:(1) The correct option is b. (2) The correct option is c.
Explanation:
(1)
It is given that the △ABD≅△FEC.
So by (CPCTC) corresponding parts of congruent triangles are congruent.

It is given that the angle DAB is 63 degree.

Therefore, the correct option is b.
(2)
It is given that the △ABD≅△FEC.
So by (CPCTC) corresponding parts of congruent triangles are congruent.




Therefore, the correct option is c.
Answer:
$5.04
Step-by-step explanation:
Take the cost of one candle and multiply the number of candles desired
6 *.84 =5.04