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PilotLPTM [1.2K]
3 years ago
6

The van traveled 120 miles in 7 hours. How long would it take to travel 1400 miles at the same speed? (A) 5/3 hrs (B) 81 2/3 hrs

(C) 49/6 hrs (D)24000 hr
Mathematics
1 answer:
trapecia [35]3 years ago
4 0

Answer:

81\frac{2}{3} hours

Step-by-step explanation:

Hi there!

<u>1) Create a proportion</u>

  • The van traveled 120 miles in 7 hours
  • The van travels 1400 miles in x hours

\frac{7h}{120mi}=\frac{x}{1400 mi}

\frac{7}{120}=\frac{x}{1400}

<u>2) Solve for x</u>

\frac{7}{120}=\frac{x}{1400}

Multiply both sides by 1400

\frac{7}{120}*1400=\frac{x}{1400}*1400

\frac{245}{3} =x

\frac{245}{3} =x

81\frac{2}{3} =x

Therefore, it would take the van 81\frac{2}{3} hours to travel 1400 miles at the same speed.

I hope this helps!

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Please answer this question​
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<h3>━━━━━━❃━━━━━━</h3>

<h3>Part one :</h3>

As it is given :

Present age of mom : Present age of son = 6 : 1

Therefore let :

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<h3>Part two :</h3>

Ages after 10 year :

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<h3>Part three :</h3>

The ages after 10 years are given in rational of 8 : 3.

Which means :

Mom's age after 10 years : Son's age after 10 years = 8 :3.

Now :

\scriptsize \purple{ \boxed{ \scriptsize \dfrac{ \text{Mom's age after 10 years}}{ \text{son's age after 10 years}}= \dfrac{8}{3} }} \star

\\  \\

So :

\small\sf \dashrightarrow \dfrac{6x + 10}{x + 10} =  \sf \dfrac{8}{3}

\\  \\

\small\sf \dashrightarrow \dfrac{3(6x + 10)}{x + 10} =  \sf \dfrac{8}{1}

\\  \\

\small \sf \dashrightarrow \dfrac{18x +30}{x + 10} =  \sf \dfrac{8}{1}

\\  \\

\small\sf \dashrightarrow \dfrac{18x +30}{1} =  \sf \dfrac{8(x + 10)}{1}

\\  \\

\small \sf \dashrightarrow 18x +30=  \sf 8(x + 10)

\\  \\

\small\sf \dashrightarrow 18x +30=  \sf 8x + 80

\\  \\

\small\sf \dashrightarrow 18x - 8x +30=  \sf 80

\\  \\

\small \sf \dashrightarrow 10x +30=  \sf 80

\\  \\

\small \sf \dashrightarrow 10x =  \sf 80 - 30

\\  \\

\small \sf \dashrightarrow 10x =  \sf 50

\\  \\

\small \sf \dashrightarrow  \dfrac{10x}{10}  =  \sf  \dfrac{50}{10}

\\  \\

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\\  \\

\small\bf \dashrightarrow x = \pink 5

\\

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We know :

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<h3>~\pmb{\cal W\frak{indy}M\frak{int}}༄</h3>
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