Thank you I needed to answer a question:)
All four quadrants
<h2>
Explanation:</h2>
We have the following inequality:
![y \leq \frac{2}{7}x+1](https://tex.z-dn.net/?f=y%20%5Cleq%20%5Cfrac%7B2%7D%7B7%7Dx%2B1)
So the first step we need to perform is to plot the line:
![y = \frac{2}{7}x+1](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B2%7D%7B7%7Dx%2B1)
![If \ x=0 \\ \\ y=\frac{2}{7}(0)+1 \\ \\ y=1 \\ \\ \\ If \ y=0: \\ \\ 0=\frac{2}{7}(x)+1 \\ \\ x=-\frac{7}{2}=-3.5](https://tex.z-dn.net/?f=If%20%5C%20x%3D0%20%5C%5C%20%5C%5C%20y%3D%5Cfrac%7B2%7D%7B7%7D%280%29%2B1%20%5C%5C%20%5C%5C%20y%3D1%20%5C%5C%20%5C%5C%20%5C%5C%20If%20%5C%20y%3D0%3A%20%5C%5C%20%5C%5C%200%3D%5Cfrac%7B2%7D%7B7%7D%28x%29%2B1%20%5C%5C%20%5C%5C%20x%3D-%5Cfrac%7B7%7D%7B2%7D%3D-3.5)
So the line passes through the points:
![(0,1) \ and \ (-3.5,0)](https://tex.z-dn.net/?f=%280%2C1%29%20%5C%20and%20%5C%20%28-3.5%2C0%29)
To find the shaded region, let us take a point, namely, the origin and test it in the inequality:
![y \leq \frac{2}{7}x+1 \\ \\ 0\leq \frac{2}{7}(0)+1 \\ \\ 0\leq 1 \ True!](https://tex.z-dn.net/?f=y%20%5Cleq%20%5Cfrac%7B2%7D%7B7%7Dx%2B1%20%5C%5C%20%5C%5C%200%5Cleq%20%5Cfrac%7B2%7D%7B7%7D%280%29%2B1%20%5C%5C%20%5C%5C%200%5Cleq%201%20%5C%20True%21)
Since this is true, then the shaded region includes this point. This is shown below and <em>as you can see the solutions exist in all four quadrants.</em>
<h2>
Learn more:</h2>
Inequalities: brainly.com/question/12890742
#LearnWithBrainly
Answer:
<u>Volume = 1.535</u>
<u />
Step-by-step explanation:
The region R is bounded by the equations:
y = √sin⁻¹x
y = √(π/2)
y = √(π/3)
x = 0
R is revolved around the x-axis so we will need f(y) for finding out the volume. We need to make x the subject of the equation and then replace it with f(y).
f(x) = √sin⁻¹x
y = √sin⁻¹x
Squaring both sides we get:
y² = sin⁻¹x
x = sin (y²)
f(y) = sin (y²)
Using the Shell Method to find the volume of the solid when R is revolved around the x-axis:
![V = 2\pi \int\limits^a_b {f(y)} \, dy](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%5Cint%5Climits%5Ea_b%20%7Bf%28y%29%7D%20%5C%2C%20dy)
The limits a and b are the equations y = √(π/2) and y = √(π/3) which bound the region R. So, a = √(π/2) and b = √(π/3).
V = 2π ![\int\limits^\sqrt{\frac{\pi }{2}}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Csqrt%7B%5Cfrac%7B%5Cpi%20%7D%7B2%7D%7D)
sin (y²) dy
Integrating sin (y²) dy, we get:
-cos(y²)/2y
So,
V = 2π [-cos(y²)/2y] with limits √(π/2) and √(π/3)
V = 2π [(-cos(√(π/2) ²)/2*√(π/2)] - [(-cos(√(π/3) ²)/2*√(π/3)]
V = 2π [(-cos(π/2)/ 2√(π/2)) - ((-cos(π/3)/ 2√(π/3))]
V = 2π [ 0 - (-0.5/2.0466)]
V = 2π (0.2443)
V = 1.53499 ≅ 1.535
Answer:
2000
Step-by-step explanation:
Number of shares after split is 5/2 times the pre split value =800*5/2 = 2000
Answer:
4.5
Step-by-step explanation:
1 yard = about 1 meter