3 years ago

A=(q+k/3)m solve for q. Please help lol.

Mathematics

1 answer:

brilliants [131]3 years ago

5 0

Answer:

q = A /m − k/ 3

Step-by-step explanation:

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11. Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

azamat

Answer:

Step-by-step explanation:

The first term is simply a(1), and is 5.

The fourth term is a(4), and is 5 + (1/6)(4-1), or 5 3/6 or 5 1/2.

The tenth term is a(10), and is 5 + (1/6)(10 - 1), or 5 + 3/2, or 6 1/2.

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3 years ago

<img src="https://tex.z-dn.net/?f=p%5E%7B2%7Dxp%5E%7B2%7D" id="TexFormula1" title="p^{2}xp^{2}" alt="p^{2}xp^{2}" align="absmidd

vichka [17]

Answer:

${p}^{4} x$

Step-by-step explanation:

1) Regroup terms.

${p}^{2} p^{2} x$

2) Use product rule.

${p}^{2 + 2} x$

3) Simplify 2 × 2 to 4.

$p ^{4} x$

Therefor, the answer is p⁴x

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3 years ago

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Could you help me with this plz

serious [3.7K]

Answer:

B. 203.403

Step-by-step explanation:

2 times 100 = 200

3 times 1 = 3

4 times 1/10 = 0.4

3 times 1/1000 = 0.003

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203 + 0.4 = 203.4

203.4 + 0.003 = 203.403

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3 years ago

How do you subtract 25-2.65

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-2.65

That is how you subtract 25 from 2.65

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find three consecutive odd integers such that the sum of the middle and largest integer is 21 more than smallest integer.

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Answer:

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Step-by-step explanation:

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3 years ago

A=(q+k/3)m solve for q. Please help lol. ​

A=(q+k/3)m solve for q. Please help lol.