The difference of the squares of two consecutive odd integers is 24. Find the integers.
1 answer:
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The most simplified version would be:
Answer:
(0, -5), (4, -2), (-16, -17)
Step-by-step explanation:
I attach your full question in the image below
The equation is
3x-4y-8=12
Which can be rewritten as
3x-4y =12 +8
3x-20 = 4y
y = (3/4)*x - 5
We need to check each individual case
(0,-5)
y = (3/4)*(0) - 5
y = -5
True
(4,-2)
y = (3/4)*(4) - 5
y = -2
True
(8,2)
y = (3/4)*(8) - 5
y = 1
False
(-16,-17)
y = (3/4)*(-16) - 5
y = -17
True
(-1,-8)
y = (3/4)*(-1) - 5
y = -23/4
False
(-40,-34)
y = (3/4)*(-40) - 5
y = -35
False
(0,-5) (4,-2) and (-16,-17) are the solutions
