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FrozenT [24]
3 years ago
14

The function f(x) is graphed on the coordinate plane.

Mathematics
2 answers:
tatiyna3 years ago
6 0
F(x) = 1/4x-1

i hope this helps!
Alona [7]3 years ago
4 0

Answer:

The correct answer is f(-2)= -2

Step-by-step explanation:


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Factorise completely
Andreyy89
1. Number that adds up to -12 and multiplied by the same # that gives u -13. Set it up like this because both are negative so, u need 1 negative and 1 positive.
(x-13)(x+1)

2. Same rule applies. GCF
8y(4y+1)

3. (x+3)(x-3)
4 0
3 years ago
What is the equation of the line in standard form?<br> 3x−y=−6 3x + y = 6 x + 6y = 9 x−6y=−9
lisabon 2012 [21]

The standard form: Ax + By = C

3x - y = -6  YES - A = 3, B = -1, C = -6

3x + y = 6   YES - A = 3, B = 1, C = 6

x + 6y = 9   YES - A = 1, B = 6, C = 9

x - 6y = -9   YES - A = 1, B = -6, C = -9

8 0
3 years ago
HELPPP
Bingel [31]

I'm not sure if it only wants you to find Equation 1 or go further and solve:

x = the number of 5c coins

y = the number of 10c coins

Equation 1: the total number of coins is 65

x + y = 65

total value of $3.80

0.05x + 0.1y = 3.8

<u>Simultaneous Equations</u>

Make one coefficient the same

10 * (0.05x + 0.1y = 3.80 = 0.5x + y = 38

x + y = 65

0.5x + y = 38

Subtract the equations

(x + y) - (0.5x + y)= 65 - 38

(x - 0.5x) + (y - y) = 65 - 38

0.5x = 27

x = 54

Substitute it into the original equation to find y.

x + y = 65

54 + y = 56

y = 65 - 54 = 11

Substitute it into the other equation to check it's right.

0.05x + 0.1y = 3.8

0.05(54) + 0.1(65) = 3.8

x = 54 5c coins

y = 11 10c coins

8 0
3 years ago
Classify the model as exponential growth or exponential decay. Identify the growth or decay factor AND the percent of increase o
sweet-ann [11.9K]
See also brainly.com/question/8975313

The growth factor is 2.

The increase is (2 -1)*100% = 100% per period.
5 0
3 years ago
What is the answer for -2y=3/4
ElenaW [278]

Answer: y= -3/8

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation

8 0
3 years ago
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