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Darya [45]
3 years ago
6

Find the square root of 200 up to two decimals

Mathematics
1 answer:
Margarita [4]3 years ago
4 0

Answer:

Erm

Step-by-step explanation:

14.14

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What is the sum of the exterior angle measures, one at each vertex, of a convex polygon with 11 sides?
Dennis_Churaev [7]
 The sum (for all polygons) of the exterior angles are 360. So, 360/11 is 32.72

hope this helps!
8 0
3 years ago
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What is the sum of -3 2/8 + 1/4
kati45 [8]
-3



-3 2/8 is the same as -3 1/4

-3 1/4 + 1/4 = -3
5 0
3 years ago
A bag contains only red marbles and blue marbles in the ratio of 3 red to 2 blue.
Airida [17]

Answer:

16

Step-by-step explanation:

create a t chart on one side put 3 and on the other put 2.

times 3 by 8 (you'll get 24) and then times 2 by 8 (you'll get 16.

7 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!
kifflom [539]

Answer:

A single card is drawn from a standard Deck of 52 cards. What is the probability of the card is a six or a spade?

Step-by-step explanation:

the answer is

1st Option : 8

13

8 0
3 years ago
Q1 : Find the inverse of the function.
Mamont248 [21]

Answer:

1. Option D is correct.

2. Option B is correct.

3. Option B is correct.

Step-by-step explanation:

Inverse function defined as the the function that undergoes the action of the other function.

A function f^{-1} is the inverse of f if whenever y =f(x) and x =f^{-1}

To find the inverse of the function:

Q1.

Given the function:  f(x) = 7x -1

Put y for f(x) and solve for x;

y= 7x -1

Add 1 both sides we get;

y + 1 = 7x

Divide both sides by 7 we get;

x = \frac{y+1}{7}

Put f^{-1}(y) for x;

f^{-1}(y) = \frac{y+1}{7}

Interchange y =x, we have

f^{-1}(x) = \frac{x+1}{7}

Q 2.

Given the function:

f(x) = x^3 - 7

Put y for f(x) and solve for x;

y = x^3-7

Add 7 both sides we get;

y + 7 =x^3

taking cube root both sides we get

x =\sqrt[3]{y+7}

Put f^{-1}(y) for x;

f^{-1}(y) =\sqrt[3]{y+7}

Interchange y =x, we have

f^{-1}(x) = \sqrt[3]{x+7}

Q3 .

Given the function:

f(x) = 5x^3 - 3

Put y for f(x) and solve for x;

y = 5x^3-3

Add 3 both sides we get;

y + 3 =5x^3

Divide both sides by 5 we get;

x^3 = \frac{y+3}{5}

taking cube root both sides we get

x = \sqrt[3]{\frac{y+3}{5} }

Put f^{-1}(y) for x;

f^{-1}(y) = \sqrt[3]{\frac{y+3}{5} }

Interchange y =x, we have

f^{-1}(x) = \sqrt[3]{\frac{x+3}{5} }




7 0
3 years ago
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