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4 years ago

How do you put 7/8 into a decimal

Mathematics

2 answers:

Bingel [31]4 years ago

5 0

Answer:

7.8

Step-by-step explanation:

USPshnik [31]4 years ago

3 0

Hey! Your answer would be 0.875. 7/8 = 0.875

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Having trouble solving this:

aliya0001 [1]

Answer:

3 $\frac{727}{1000}$

6 0

3 years ago

What are polynomials

Sindrei [870]

Answer/Explanation:

Polynomials are expressions with variables like x.

Polynomials may use:

Addition +
Subtraction -
Multiplication *

Non-negative numbers as exponents $^{2}$

For example: $7x^{2}y^{3} +2y^{2}-x$

Although they don't use devision, you can use division between 2 polynomials. For example:

$\frac{7x^{2}y^{3} +2y^{2}-x}{3x^{3}y^{2}+x^{2} +2y}$

4 0

3 years ago

I really need help with this question

lilavasa [31]

Answer:

a) 625; 625; right triangle

b) 205; 256; obtuse triangle

Step-by-step explanation:

The squares are values found in your memory or using a calculator. It is straightforward addition to find their sum.

7² +24² = 49 +576 = 625

25² = 625

The sum of the squares of the short sides is the square of the long side, so this is a right triangle.

<h3>right side</h3>

6² +13² = 36 +169 = 205

16² = 256

The long side is longer than is needed to form a right triangle, so the largest angle is more than 90°. This is an <em>obtuse triangle</em> (as shown).

5 0

2 years ago

74.64 rounded to the nearest tenth<br> how do you round a decimaled number?

Irina18 [472]

Answer:

$\displaystyle 74,6$

Step-by-step explanation:

You have a <em>6</em> in the tenths position, so the <em>4</em> in the <u>hundredths</u> position tells you to STAY at $\displaystyle 74,6.$

I am joyous to assist you at any time.

5 0

2 years ago

A tank contains 250 liters of fluid in which 20 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu

Vilka [71]

Answer:

$A(t)=250-230e^{-\frac{t}{50} }$

Step-by-step explanation:

A(t) is the amount of salt in the tank at time t.

dA / dt = rate of salt flowing into the tank - rate of salt going out of the tank

dA / dt = (1 g/L)*(5 L/min) - (A(t)/250 g/L) * (5L/min)

dA / dt = 5 g/min - (A(t) / 50) g/min

$\frac{dA}{dt}+\frac{A(t)}{50} = 5\\\\The\ integrating\ factor(IF)= e^{\int\limits \frac{1}{50}dt }=e^{\frac{t}{50} }\\\\Multiplying\ through\ by\ the\ I.F:\\\\\frac{dA}{dt}*e^{\frac{t}{50} }+\frac{A(t)}{50}*e^{\frac{t}{50} } = 5*e^{\frac{t}{50} }\\\\Integrating \ both \ sides:\\\\\int\limits[ \frac{dA}{dt}*e^{\frac{t}{50} }+\frac{A(t)}{50}*e^{\frac{t}{50} }] dt=\int\limits 5e^{\frac{t}{50} } dt\\\\A(t)e^{\frac{t}{50} } =\int\limits 5e^{\frac{t}{50} } dt\\\\$

$A(t)e^{\frac{t}{50} } =250e^{\frac{t}{50} }+C\\\\A(t)=250+Ce^{-\frac{t}{50} }\\\\But\ A(0) = 20\\\\20=250+Ce^{-\frac{0}{50} }\\\\C+250=20\\\\C=-230\\\\A(t)=250-230e^{-\frac{t}{50} }$

7 0

3 years ago