Answer/Explanation:
Polynomials are expressions with variables like x.
Polynomials may use:
- Addition +
- Subtraction -
- Multiplication *
- Non-negative numbers as exponents

For example: 
Although they don't use devision, you can use division between 2 polynomials. For example:

Answer:
a) 625; 625; right triangle
b) 205; 256; obtuse triangle
Step-by-step explanation:
The squares are values found in your memory or using a calculator. It is straightforward addition to find their sum.
<h3>left side</h3>
7² +24² = 49 +576 = 625
25² = 625
The sum of the squares of the short sides is the square of the long side, so this is a right triangle.
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<h3>right side</h3>
6² +13² = 36 +169 = 205
16² = 256
The long side is longer than is needed to form a right triangle, so the largest angle is more than 90°. This is an <em>obtuse triangle</em> (as shown).
Answer:

Step-by-step explanation:
You have a <em>6</em> in the tenths position, so the <em>4</em> in the <u>hundredths</u> position tells you to STAY at 
I am joyous to assist you at any time.
Answer:

Step-by-step explanation:
A(t) is the amount of salt in the tank at time t.
dA / dt = rate of salt flowing into the tank - rate of salt going out of the tank
dA / dt = (1 g/L)*(5 L/min) - (A(t)/250 g/L) * (5L/min)
dA / dt = 5 g/min - (A(t) / 50) g/min
![\frac{dA}{dt}+\frac{A(t)}{50} = 5\\\\The\ integrating\ factor(IF)= e^{\int\limits \frac{1}{50}dt }=e^{\frac{t}{50} }\\\\Multiplying\ through\ by\ the\ I.F:\\\\\frac{dA}{dt}*e^{\frac{t}{50} }+\frac{A(t)}{50}*e^{\frac{t}{50} } = 5*e^{\frac{t}{50} }\\\\Integrating \ both \ sides:\\\\\int\limits[ \frac{dA}{dt}*e^{\frac{t}{50} }+\frac{A(t)}{50}*e^{\frac{t}{50} }] dt=\int\limits 5e^{\frac{t}{50} } dt\\\\A(t)e^{\frac{t}{50} } =\int\limits 5e^{\frac{t}{50} } dt\\\\](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%2B%5Cfrac%7BA%28t%29%7D%7B50%7D%20%3D%205%5C%5C%5C%5CThe%5C%20integrating%5C%20factor%28IF%29%3D%20e%5E%7B%5Cint%5Climits%20%5Cfrac%7B1%7D%7B50%7Ddt%20%7D%3De%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%5C%5C%5C%5CMultiplying%5C%20through%5C%20by%5C%20the%5C%20I.F%3A%5C%5C%5C%5C%5Cfrac%7BdA%7D%7Bdt%7D%2Ae%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%2B%5Cfrac%7BA%28t%29%7D%7B50%7D%2Ae%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%20%3D%205%2Ae%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%5C%5C%5C%5CIntegrating%20%5C%20both%20%5C%20sides%3A%5C%5C%5C%5C%5Cint%5Climits%5B%20%20%5Cfrac%7BdA%7D%7Bdt%7D%2Ae%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%2B%5Cfrac%7BA%28t%29%7D%7B50%7D%2Ae%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%5D%20dt%3D%5Cint%5Climits%20%205e%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%20dt%5C%5C%5C%5CA%28t%29e%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%20%3D%5Cint%5Climits%20%205e%5E%7B%5Cfrac%7Bt%7D%7B50%7D%20%7D%20dt%5C%5C%5C%5C)
