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shusha [124]
3 years ago
11

Graph the function. g(x)=3/4*2^x

Mathematics
1 answer:
3241004551 [841]3 years ago
5 0

Answer:

I put the equation into desmos online graphing calculator

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A parent is using a garden hose to fill up a small inflatable pool for her young child. The
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Answer:

The independent is the 90 gallons and the dependent is the 8 minutes.

Hope this helps!

Step-by-step explanation:

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If you are given the surface area of a square pyramid and the area of the base, how could you calculate the area of each side of
stiv31 [10]

Answer:

you need to divide the surface are and the base and you should get the number of each lateral face

Step-by-step explanation:

but you do need to tell me the numbers so do that in the comments

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3 years ago
Madison loves her stuffed dolphin toy. The toy is 27 inches long. If her brother came and sliced the dolphin in half what would
Alik [6]
The size of the dolphin would be 13.5 inches long because half of 27 is 13.5.

27/2 = 13.5
3 0
4 years ago
Read 2 more answers
I NEED HELP!!!
Ierofanga [76]
Standard equation for a circle is: (x -h)² + (y - k)² = r²
(h,k) is the center which is given to be: (0,0) so you just need the radius.
The radius is the distance from the center to the point (-4,5) on the edge.

Use the distance formula

d = √[(-4 - 0)² + (5 -0)²]
d = √[16 + 25]
d = √[41]

radius is √[41]
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7 0
3 years ago
The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
blagie [28]

Answer:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

Step-by-step explanation:

For this case we can define the variable of interest amount of Pb209 and for the half life would be given:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

4 0
4 years ago
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