Given linear equation in standard form x-y=-2.
Let us convert it in slope-intercept form first.
x-y =-2.
Subtracting x from both sides
x-x-y = -2-x
-y = -x-2.
Dividing both sides by -1, we get
y= x+2.
We can write it as y=1x+2.
Let us compare it with slope-intercept form y=mx+b.
On comparing, we get slope m= 1 and y-intercept b=2.
Let us check option -3x+3y=6.
Let us check it by converting in slope-intercept form.
Adding 3x on both sides we get
-3x+3x+3y=6+3x
3y = 3x + 6.
Dividing both sides each term by 3.
3y/3 = 3x/3 + 6/3.
y= 1x +2.
On comparing with slope-intercept form y=mx+b.
We got slope m=1 and y-intercept =2.
So, the equation in option B) -3x+3y=6 create a consistent and dependent system with x-y=-2.
We can tell that the whole L shaped angle is 90 degrees because it has the little box in the corner. Now, the 90 degree angle is split into two parts with that line coming from the box. Those two parts of the whole 90 degree angle add up to 90 degrees.
90 = 4v + 2 + 9v - 3
Now, let's solve for v. Combine like terms.
90 = 13v - 1
Add 1 to both sides.
91 = 13v
Divide both sides by 13
7 = v
I believe that would be 0.4691g
Answer:
a = - 2 , b = 8
Step-by-step explanation:
Since the points p and q lie on the graph then they satisfy the equation
(6, 4 ) , substitute x = 6 , y = 4 into the equation
6a + 4b = 20 → (1)
(2, 3 ) , substitute x = 2, y = 3 into the equation
2a + 3b = 20 → (2)
Multiplying (2) by - 3 and adding to (1) will eliminate a
- 6a - 9b = - 60 → (3)
add (1) and (3) term by term to eliminate a
0 - 5b = - 40
- 5b = - 40 ( divide both sides by - 5 )
b = 8
Substitute b = 8 into either of the 2 equations and solve for a
Substituting into (1)
6a + 4(8) = 20
6a + 32 = 20 ( subtract 32 from both sides )
6a = - 12 ( divide both sides by 6 )
a = - 2
