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Romashka-Z-Leto [24]
3 years ago
7

How do you do 27 divided by 624 in partial quotients

Mathematics
2 answers:
Virty [35]3 years ago
6 0

Answer:

Step-by-step explanation:

For this case we have the following numbers:

624

27

When dividing both numbers, we observe that:

The partial quotient of the division is equal to 23

The rest of the division is equal to 3.

Note: See attached image to see the procedure of the division between both numbers.

Answer:

the partial quotient of 624 divided by 27 is:

23

CaHeK987 [17]3 years ago
6 0

Answer:

23 1/9

Step-by-step explanation:

624 divided by 27 equals

23 with a remainder of 3

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What is the least common multiple of 8 and 11
tino4ka555 [31]

Answer:

88

Step-by-step explanation:

Find the prime factorization of both 8 and 11.

8 → 4 × 2 → 2 × 2 × 2

11 → 11

Then, multiply each factor the greater number of times it occurs. Since no factors are duplicated between 8 and 11 (as in, 2 is not a factor of 11, nor is 11 a factor of 8), LCM will equal 2 × 2 × 2 × 11.

2 × 2 × 2 × 11 = 88, so the LCM is 88.

It's a little hard to explain without visuals. A video could be useful, though I can't put links here.

7 0
3 years ago
Solve 4X^2+7 = 8X +4 by using the quadratic formula
Sergio [31]

Answer:

(1.5,0)

(.5,0)

Step-by-step explanation:

Quadratic formula below

We first need to move everything to one side of the equation

4x²-8x+3=0

Then plug everything in

(8±√(-8²-4*4*3))/(2*4)

(8±√16)/8

To calculate the ± we need to do when where it's adding and then negative

we have

(8+4)/8=3/2

and hten

(8-4)/8=1/2

4 0
3 years ago
F(x) = x^2 + 1 is limited to (0, 1, 2, 3), what is the maximum love you all of the range?
wlad13 [49]

Answer:

2

Step-by-step explanation:

f(x)=x^2+1

now,

f(1)=1^2+1

=1+1

=2

4 0
3 years ago
Pls help<br> me i really am behind
Lemur [1.5K]

Answer:

A

Step-by-step explanation:

(8-3^2)*9-6

8-9*9-6

-1*9-6

-9-6

-15

5 0
2 years ago
Which table represents a quadratic relationship?
svp [43]

In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

B. First differences are 128-135 = -7, 105-128 = -23, 72-105 = -33. Second differences are -23-(-7) = -16, -33-(-23)=-10. Since -16 ≠ -10, this relation is not quadratic. (It is cubic, since 3rd differences are constant at +4.)

C. First differences are -23.2-(-23.4) = 0.2, -23.0-(-23.2) = 0.2, -22.8-(-23.0) = 0.2. Second differences are zero, so this is not a quadratic relation. (It is linear, with a slope of 0.2.)

D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

The appropriate choice is ...

... D. x -1 0 1 2 3 4

... f(x) 90 56 26 0 -22 -40

4 0
3 years ago
Read 2 more answers
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