Please help and I'll love you foreverrrrr no joke!!!

1 answer:

4 0

Only like sedans: 25- 15 = 10

Only like hatchbacks: 40-15 = 25

Like both: 15

Like none of them: 100-10-25-15 = 50

Dislike sedans: 100 - 10-15 = 75

Dislike hatchbacks: 100-25-15 = 60

So dislikes: sedans>hatchbacks

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What’s the domain and range for these two?

user100 [1]

Step-by-step explanation:

1) the domain is from -3 to 5 D [-3,5]

the range is from -5 to -2. R [-5,-2]

2)the domain is from -3 to 6 but not including 6 D [-3,6)

the range is from -5 but not including -5 to 2. R (-5,2]

4 0

2 years ago

1. Which equation should be used to find the area of the triangle below? *

77julia77 [94]

Answer:

See Explanation

Step-by-step explanation:

Required

Expression for area of triangle

This is calculated using

$Area = \frac{1}{2} * base * height$

Assume that:

$base = 5cm; height = 2cm$

The equation becomes

$Area = \frac{1}{2} * 5* 2$

8 0

2 years ago

The equation y=9. 5x 0. 4 represents the line of best fit for the distance (in feet) that Marcella traveled over time (in second

Bas_tet [7]

The average speed of Marcella in feet per seconds is 9.5 feet per second.

<h3>How are time taken for travel, distance traveled, and the average speed are related?</h3>

We have this below shown relation between them

$\text{Average speed} = \dfrac{\text{Distance traveled}}{\text{Total time taken to travel that distance}}\\\\or\\\\\text{Total time taken to travel that distance}= \dfrac{\text{Distance traveled}}{\text{Average speed} }$

For the given case, we have:

The equation $y=9.5x + 0.4$ represents the line of best fit for the distance (in feet) that Marcella traveled over time (in seconds)

The line of best fit can be taken as approximately telling about the data points ( y = distance traveled in feet, and x = time spent )

Let the initial time be 'x' with initial distance traveled 'y', then the time after one second will be (x+1), and the distance traveled be $y_1$

The value of y and $y_1$ are calculated as:

$y = 9.5x + 0.4\\y_1 = 9.5(x+1) + 0.4 = 9.5x + 9.9$

Thus, the average speed is calculated at time 'x' as:

$\text{Average speed} = \dfrac{\text{Distance traveled}}{\text{Total time taken to travel that distance}}\\\\or\\\\\text{Average speed} = \dfrac{y_1 - y}{x + 1 - x} = \dfrac{9.5x + 9.9 - 9.5x - 0.4}{1} = 9.5 \: \rm feet/sec$