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neonofarm [45]
3 years ago
9

Assume a and b are whole numbers, and a>b. Which expression has the least value?

Mathematics
1 answer:
dedylja [7]3 years ago
8 0

a > b

A . a^5b^3/ab^4 = a^4/b

B. a^4 / a*a*a*a = a^4 / a^4 = 1

C. ab^2 / a^2b = b/a

D. b*b*b/b^3 = b^3/b^3 = 1

B and D, doesn't matter what values of a and b it's always equal 1

Lets say a = 2 and b = 1

A. a^4/b = 2^4 / 1 = 16/1 = 16

C. b/a = 1/2 = 0.5

So C has the least value

Answer:

ab^2 / a^2b

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Answer:

Her answer is wrong because she the object cannot hit the ground at negative seconds. She could’ve have used other methods because she used the quadratic formula. The advantages is that it works for every situation. The disadvantages is that it takes longer. She should’ve used a different method.

Step-by-step explanation:

4 0
3 years ago
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A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?
kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

f(x)=\frac{1}{2^{2x}}   (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]  (2)

To solve this derivative you use the following derivative formula:

\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

-2(ln2)2^{-2x}=-1

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235

With this value you calculate f(a):

f(a)=\frac{1}{2^{2(0.235)}}=0.721

Next, you use the general equation of line:

y-y_o=m(x-x_o)

for xo = a = 0.235 and yo = f(a) = 0.721:

y-0.721=(-1)(x-0.235)\\\\y=-x+0.956

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

0=-x+0.956\\\\x=0.956

hence, the x-intercept of the tangent line is 0.956

5 0
3 years ago
Given v=(6,3) and w=(1,-2), what is the result of v-w
Daniel [21]
Here, v - w would be (6-1, 3-[-2]), or (5, 5).  
I don't believe you need the word "result" here.  At first I thought you'd meant "resultant."  Here you're finding the "difference" v less w.



3 0
3 years ago
Consider a standard deck of 52 playing cards with 4 suits. If A is the event of drawing a 6 from the deck, and B is the event of
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Answer: Intersection of A and B = 2

Step-by-step explanation:

Total cards = 52

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Total  black playing card =26

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hence, Intersection of A and B = 2

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3 years ago
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