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liq [111]
3 years ago
15

A polynomial function P(x) with rational coefficients has the given roots find two additional roots of P(x)=0 i and 7+8i

Mathematics
2 answers:
leonid [27]3 years ago
8 0

Answer:

As, the given polynomial is P(x)=0,

It is given that two of it's roots are i and 7+ 8 i.

If this quadratic equation has four roots, there is no effect whether the powers of x has rational or any real coefficients.Why i have written this because imaginary roots or non real roots occur in pairs.

It is not necessary that this polynomial has only four roots, but number of non real root or imaginary root will be even.

So, if P(x)=0, has two roots → i and 7+ 8 i, other two roots will be -i and 7- 8 i.




den301095 [7]3 years ago
3 0
Note that if a + bi is a root of P(x) = 0, then a – bi is also a root of P(x) = 0.

In this case, i and 7 + 8i are two roots of P(x) = 0. So –i and 7 – 8i are two additional roots of P(x) = 0.
 
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In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.
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Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

<u>Solution:</u>

Given that,

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<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>

\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100

\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}

<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>

\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

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