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yulyashka [42]
4 years ago
6

Ian has $28 in his checking account. If he writes a check for $12, how much money is left in his account?

Mathematics
2 answers:
k0ka [10]4 years ago
3 0
Answer:
$16

Explanation:
$28 - $12
musickatia [10]4 years ago
3 0

Answer:

$16

Step-by-step explanation:

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MAVERICK [17]
They are there unit distance away from each other
8 0
3 years ago
How do you solve the equation 7^(7n+7)=2,401
RoseWind [281]
7^(7n + 7) = 2401
apply log on both sides to solve the equation
log 7^(7n + 7) = log 2401
the power is brought forward
(7n + 7) log 7 = log 2401
7n +7 = log 2401 / log 7
7n + 7 = 4
7n = -3
n = -3/7

Hope it helped!
5 0
3 years ago
V5. Suppose you invest $5,000 at 9% interest, compounded annually, for 10 years. Determine the future value of your investment,
Elanso [62]

Answer: $11836.8

Step-by-step explanation:

Given. That :

Amount invested = $5000

Interest rate = 9% = 0.09

Period = 10 years, compounded annually

Using the compound interest formula :

A = p(1 + r/n)^nt

A = final amount

P = principal or invested amount

r = rate of interest

n = number of times interest Is applied per period

t = period

A = 5000(1 + 0.09/1)^(1*10)

A = 5000(1.09)^10

A = 5000 * 2.36736367459211723401

A = 11836.81837296058617005

= $11836.8

4 0
3 years ago
WILL MARK BRAINLIEST <br><br> what is the domain of (f/g) (x)?
tatyana61 [14]

Given that f(x) = \sqrt{7-x} and g(x) = \sqrt{x + 2}, we can say the following:

\Bigg(\dfrac{f}{g}\Bigg)(x) = \dfrac{f (x)}{g(x)} = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}


Now, remember what happens if we have a negative square root: it becomes an imaginary number. We don't want this, so we want to make sure whatever is under a square root is greater than 0 (given we are talking about real numbers only).


Thus, let's set what is under both square roots to be greater than 0:

\sqrt{7 - x} \Rightarrow 7 - x \geq 0 \Rightarrow x \leq 7

\sqrt{x + 2} \Rightarrow x + 2 \geq 0 \Rightarrow x \geq -2


Since both of the square roots are in the same function, we want to take the union of the domains of the individual square roots to find the domain of the overall function.

x \leq 7 \,\,\cup x \geq -2 = \boxed{-2 \leq x \leq 7}


Now, let's look back at the function entirely, which is:

\Bigg( \dfrac{f}{g} \Bigg)(x) = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}

Since \sqrt{x + 2} is on the bottom of the fraction, we must say that \sqrt{x + 2} \neq 0, since the denominator can't equal 0. Thus, we must exclude \sqrt{x + 2} = 0 \Rightarrow x + 2 = 0 \Rightarrow x = -2 from the domain.


Thus, our answer is Choice C, or \boxed{ \{ x | -2 < x \leq 7 \}}.


<em>If you are wondering why the choices begin with the x | symbol, it is because this is a way of representing that x lies within a particular set.</em>

6 0
3 years ago
A pilot flew a small plane against the wind 1 miles from Ashland to Roseberg in hour. The pilot returns with the wind miles to A
Maru [420]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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