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kiruha [24]
3 years ago
13

IS 1/2 BIGGER THAN 1/4

Mathematics
2 answers:
Nesterboy [21]3 years ago
6 0
Yes, think of it like money. 1/4 = .25 cents.
1/2= .50 cents. what is bigger / more?
natali 33 [55]3 years ago
5 0

Answer: yes, because 1/4 is = to 0.25 and 1/2 is = to 0.5


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A(x+1)(x-1)+b(x-2)(x+1)+(x+1)^2=9x-x-10 What is a+b?
igor_vitrenko [27]

a(x+1)(x-1)+b(x-2)(x+1)+(x+1)^2=9x^2-x-10

(x+1)(a(x-1)+b(x-2)+(x+1))=(x+1)(9x-10)

a(x-1)+b(x-2)+x+1=9x-10

Now this equation is much simpler!

(a+b)x-a-2b+x+1=9x-10

(a+b)x-a-2b=8x-11

(a+b-8)x-a-2b-11=0

a+b-8=(a+2b-11)/x

I can't solve it 3 variables and 1 equations means infinite answers so yea.

4 0
3 years ago
Consuela and her three friends order 2 pizzas. Consuela cuts each pizza into 8 equal slices. She saves 2 slices of pizza for her
Akimi4 [234]
Let
x-------------->  the number of slices eating by Consuela  and her <span>three friends

we know that
[total slices]=8*2=16 slices
</span><span>[slices of pizza for her older brother]=2
x=16-2=14 slides
</span><span>Consuela and her friends share the rest of the pizza, each eating the same number of slices---------> 14/4= 3.5 slides of pizza each  (</span><span>this part is not necessary, but it is shown in a didactic way)
</span><span>
the question is 
</span><span>What fraction of the 2 pizzas is left over?
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<span>
the answer is (1/8)

</span>
8 0
3 years ago
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Lapatulllka [165]

the answer is 1 hour and 1/4 of a minute

4 0
3 years ago
Read 2 more answers
Pls hurry I’m being
kati45 [8]
D. Warm air rises and cool air sinks
7 0
3 years ago
Suppose that a cyclist began a 476
mojhsa [17]
Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus    \bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;\textit{eastbound cyclist}&d&r&8.5\\&#10;\textit{westbound car}&476-d&r+33.2&8.5&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;\begin{cases}&#10;\boxed{d}=8.5r\\\\&#10;476-d=(r+33.2)8.5\\&#10;----------\\&#10;476-\boxed{8.5r}=(r+33.2)8.5&#10;\end{cases}

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2
6 0
3 years ago
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