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kiruha [24]
3 years ago
13

IS 1/2 BIGGER THAN 1/4

Mathematics
2 answers:
Nesterboy [21]3 years ago
6 0
Yes, think of it like money. 1/4 = .25 cents.
1/2= .50 cents. what is bigger / more?
natali 33 [55]3 years ago
5 0

Answer: yes, because 1/4 is = to 0.25 and 1/2 is = to 0.5


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The best synonym for that kind of legend is key. Hope this helps.
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The chess club members bought six tickets to a tournament for $15. how much would they have paid if all nine members wanted to g
ElenaW [278]
15/6=2.5
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$22.50 is your answer

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Question 5 of 5
makvit [3.9K]

Answer:what happened to  c and a

Step-by-step explanation:

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2 years ago
Answer what you can please!
Fed [463]

Answer:

Something's Fishy:

Domain = Time

Range = Gallons of water remaining.

Smart Phone, but is it a Smart Deal?

Domain = Weeks passing

Range = Interest ($)!!!!

Step-by-step explanation:

Something's Fishy:

First and foremost, Candice, very gently, removes the fish from the tank and places them into a clean, healthy, temporary environment.

AKA Candice glances to check if the coast is clear before chucking the fish into the nearest toilet as fast as possible. (Stop laughing, Fish deserve equal rights too [no, but really]).

Candice then begins to empty the tank, draining 10 gallons per minute.

Again, if you know anything of physics or mathmatical graph placement, the TIME variable will 9.99999999/10x be the independent variable, this won't change. Make it a rule of thumb, get the sharpie-tat, do whatever you need to do to remember it.

From a literal perspective, we can see that the water is draining at a constant rate. The rate isn't changing, but something IS. That "something" is the water remaining IN the tank per periodic interval.

Time is independent.

Puny water is dependent and inferior.

The fish are depending upon the hope that the one gassy guy from IT doesn't get to the toilet before Candice comes back.

The fate of the fish are dependent upon hoping the guy from IT doesn't have beans and cheese for lunch. (Remember Pompeii?! Anyone? Imagine Pompeii in a 2x2 ceramic & plastic can now :). You're welcome!)

End of story.

Smart Phone, but is it a smart deal?

Your cousin is ripping you off. He knows it, his momma knows it, and the dog knows that it's hungry, and it will definitely eat the phone. Yeah, the dog knows it too.

Every week that passes, cuzzo gets double the cash from you to pocket. It's all fun and games until 30 weeks have passed and you're two-feet in the grave of debt, because you always chose McDonalds over settling debts.

Because CUZZO (that conniving worm) knew that your INTEREST was dependent upon the number of weeks it'd take you to pay cuzzo his cash back.

Hope this helps!!

(No fish were harmed in the making of this post)

8 0
3 years ago
Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A
Vlad [161]

Answer:

y(x)=sin(2x)+2cos(2x)

Step-by-step explanation:

y''+4y=0

This is a homogeneous linear equation. So, assume a solution will be proportional to:

e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda

Now, substitute y(x)=e^{\lambda x} into the differential equation:

\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0

Using the characteristic equation:

\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0

Factor out e^{\lambda x}

e^{\lambda x}(\lambda ^2 +4) =0

Where:

e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda

Therefore the zeros must come from the polynomial:

\lambda^2+4 =0

Solving for \lambda:

\lambda =\pm2i

These roots give the next solutions:

y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}

Where c_1 and c_2 are arbitrary constants. Now, the general solution is the sum of the previous solutions:

y(x)=c_1 e^{2ix} +c_2 e^{-2ix}

Using Euler's identity:

e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)

y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\

Redefine:

i(c_1-c_2)=c_1\\\\c_1+c_2=c_2

Since these are arbitrary constants

y(x)=c_1sin(2x)+c_2cos(2x)

Now, let's find its derivative in order to find c_1 and c_2

y'(x)=2c_1 cos(2x)-2c_2sin(2x)

Evaluating    y(0)=2 :

y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2

Evaluating     y'(0)=2 :

y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1

Finally, the solution is given by:

y(x)=sin(2x)+2cos(2x)

5 0
3 years ago
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