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3 years ago

Pay:11.71 per hourhours:11 hours per week

Mathematics

2 answers:

Tema [17]3 years ago

6 0

Week = 128.81
Month = 515.24
Year = 6182.88
I believe this is all correct :)

defon3 years ago

4 0

Answer:

$128.81 per week

$515.24 per month

$6182.88 per year

Step-by-step explanation:

$\frac{11.71}{y} :\frac{1}{11}$

y = 128.81

$\frac{128.81}{y} :\frac{1}{4}$

y = 515.24

$\frac{515.24}{y}: \frac{1}{12}$

y = 6182.88

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3 years ago

X>0 and 2x^2+3x-2=0 what is the value of x

vladimir2022 [97]

Step-by-step explanation:

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3 years ago

Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"

vampirchik [111]

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h$

Employ a standard trick used in proving the chain rule:

$\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h$

The limit of a product is the product of limits, i.e. we can write

$\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)$

The rightmost limit is an exercise in differentiating $\sqrt x$ using the definition, which you probably already know is $\dfrac1{2\sqrt x}$ .

For the leftmost limit, we make a substitution $y=\sqrt x$ . Now, if we make a slight change to $x$ by adding a small number $h$ , this propagates a similar small change in $y$ that we'll call $h'$ , so that we can set $y+h'=\sqrt{x+h}$ . Then as $h\to0$ , we see that it's also the case that $h'\to0$ (since we fix $y=\sqrt x$ ). So we can write the remaining limit as

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}$

which in turn is the derivative of $\tan y$ , another limit you probably already know how to compute. We'd end up with $\sec^2y$ , or $\sec^2\sqrt x$ .

So we find that

$\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}$

7 0

4 years ago

The mean is μ = 15.2 and the standard deviation is σ = 0.9. find the probability that x is greater than 17.

Vlad1618 [11]

The probability that x >17 will be found as follows:
the z-score is given by:
z=(17-15.2)/0.9=2
Thus
P(X>17)=1-P(x<17)=P-(z=2)
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8 0

3 years ago

Read 2 more answers

Plz help due today giving brainliest!

Artyom0805 [142]

Answer:

The answers are C, D, A, and B.

Step-by-step explanation:

Hope this helps :D

8 0

3 years ago

Pay:11.71 per hourhours:11 hours per week​

Pay:11.71 per hourhours:11 hours per week