All categories

2 years ago

Which triangle has congruent angles? Select one: a. isosceles b. right c. equilateral d. obtuse

Mathematics

1 answer:

Svetllana [295]2 years ago

5 0

Answer:

Congruent means all the same size and shape

Equilateral triangle has all the sides the same length, so it would be equilateral

Step-by-step explanation:

You might be interested in

Reducing fraction 80/100

IceJOKER [234]

Answer:

4/5 is fully reduced

Step-by-step explanation:

4 0

3 years ago

5. Pete and Mike share £420 in the ratio 5:1. How much does Pete have.

sdas [7]

Answer:

5+1=6

5/6 x420

5x70=350

Step-by-step explanation:

7 0

2 years ago

Please help (screenshot included)

umka2103 [35]

Answer:

16 hours

Step-by-step explanation:

company A $800 plus $16 per hour

company B $720 plus $21 per hour

im going to start with 10 and go from there

company A

16 x 10 = 160

800 + 160 = 960

company B

21 x 10 = 210

720 + 210 = 930

it needs to go up so lets try 15

company A

16 x 15 = 240

800 + 240 = 1040

company B

21 x 15 = 315

720 + 315 = 1035

one more maybe 16

company A

16 x 16 = 256

800 + 256 = 1056

company B

21 x 16 = 336

720 + 336 = 10 56

4 0

2 years ago

Read 2 more answers

I’m really rusty with trigonometric functions

alexgriva [62]

Answer:

Step-by-step explanation:

hypotenuse is $\sqrt{202\\} \\\\\\\\$

because 14^2 + 3^2 = c^2

sin is = $\frac{3\sqrt{202} }{202}$

cos is = $\frac{14\sqrt{202} }{202}$

tan is $\frac{3}{14}$

4 0

2 years ago

The given line passes through the points (0, -3) and (2, 3).

puteri [66]

The equation, in point-slope form of the line that is parallel to the given line and passes through the point (-1, -1) is y + 1 = 3(x + 1).

<u>Solution:</u>

Given that, a line passes through (0, -3) and (2, 3).

We have to find the line equation which is parallel to above line and passes through (-1, -1).

Now, let us find the slope of the given line.

$\text { slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}, \text { where }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are points on that line }$

$\text { Then, } m=\frac{3-(-3)}{2-0}=\frac{3+3}{2}=\frac{6}{2}=3$

So, slope of given line is 3,

Then, slope of required line is also 3, as slopes of parallel lines are equal.

Then, required line equation in point – slope form is given as:

$\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right)} \\\\ {y-(-1)=3(x-(-1))} \\\\ {\rightarrow y+1=3(x+1)}\end{array}$

Hence, the line equation is y + 1 = 3(x + 1).

6 0

3 years ago