1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eduardwww [97]
3 years ago
6

 Sandra sells necklaces at a school craft fair. She uses the equation P= 7.5n - (2.25n + 15) to determine her total profit at th

e fair. Based on this equation, how much does she charge for each necklace?
A. $2.25
B. $7.50
C. $15.00
D. $17.25

This question has been posted with answers...but I am not in understanding. Would someone mind explaining WHY the answer is $7.50? Why wouldn't it be $2.25?
Mathematics
1 answer:
gregori [183]3 years ago
8 0
The way you find profit is to subtract the revenue and the cost
Profit = Revenue - Cost
The revenue is the amount of money coming in, the cost is the amount of money going out. The goal of course is to have the revenue larger than the cost so that the profit is positive. 

So the equation given is
P = 7.5n - (2.25n+15)
and its in the form
P = R - C
where...
R = 7.5n is the revenue equation
C = 2.25n+15 is the cost equation

Focus on the revenue equation
R = 7.5n
which is the same as 
R = 7.50*n

This tells us that Sandra pulls in a total of 7.50*n dollars where n is some positive whole number. It represents the number of necklaces sold. For example, if she sold n = 10 necklaces, then
R = 7.50*n
R = 7.50*10
R = 750
meaning that Sandra has made $750 in revenue

As you can see above, the revenue is computed by multiplying the price per necklace ($7.50) by the number of necklaces sold (n) to get R = 7.50*n

So that's why the answer is $7.50

Note: The 2.25 is part of the cost equation. This is known as the variable cost. It is the cost to make one necklace ignoring the fixed cost (eg: rent). The variable cost often doesn't stay the same, but algebra textbooks often simplify this aspect. 
You might be interested in
In Brownsville Texas it is 80°F the temperature is expected to drop 1.5° each hour in Mesquite Texas is 94°F and the temperature
denis-greek [22]

Answer:

28 hours

Step-by-step explanation:

let the time period at which the temperature be equal in both Brownsville and Mesquite Texas be 'x'.

Given,

In Brownsville Texas, the temperature is expected to drop 1.5° each hour and In Mesquite Texas, the temperature is expected to drop 2° each hour.

Now, according to the question,

after 'x' hours,

⇒ 80° - 1.5°(x) = 94° - 2°(x)

⇒ 0.5°(x) = 14°

⇒ x = 28

Hence, Till 28 more hours the temperature in Mesquite Texas be greater than that in Brownsville.

3 0
3 years ago
Help me i dont know what i am doing at all
nika2105 [10]
You are doing the distributive property.
68.5j+76.54
7 0
3 years ago
Convert 4/7 to decimals using long divison​
Elena-2011 [213]
I think it’s 1.75 sorry if this is wrong
3 0
2 years ago
Kevin made a jewelry box with dimensions shown 5cm,10cm,15cm what is the value of the jewelry box?
zaharov [31]

Answer:

750

Step-by-step explanation:

10 times 5 times 15

3 0
3 years ago
Find the area of a square whose side in 7 inches (remeber A=b×h)
viva [34]
The area is 14. your welcome
7 0
3 years ago
Read 2 more answers
Other questions:
  • What is the value of x? enter your answer, as a decimal, in the box. ft triangle m n p with segment a b parallel to segment n p
    13·2 answers
  • Dividing integers.word problems.
    9·1 answer
  • What are the x-coordinates of the solutions to this system of equations?
    15·1 answer
  • Is equation w+ 3√4x=4 linear?
    12·2 answers
  • Anyone know the answers ? this is precal​
    6·1 answer
  • 10÷652.3 please help me​
    15·2 answers
  • Can someone plz help me with dis i will give brainliest
    8·2 answers
  • Find the equation of a line that has slope, m, of
    12·1 answer
  • Someone help me with this geomtry question asap....no links pls
    6·1 answer
  • Which number completes the system of linear
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!