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3 years ago

Lines x and y are parallel.

Mathematics

2 answers:

sveticcg [70]3 years ago

8 0

Answer: C is not true

Step-by-step explanation:

I can't really explain why c is not true but I know for sure that A, B, and D are True.

frosja888 [35]3 years ago

5 0

Answer:

Option C.

Step-by-step explanation:

Option A. The given lines x and y are parallel and line s is a transverse.

Therefore, ∠1 and angle (6x + 8°) will be equal as they are corresponding internal angles. Option A is true.

Option B. ∠1 + 106° = 180° ( supplementary angles )

∠1 = 180 - 106 = 74° Option B is also true

Option C. x and y are parallel lines and t is the transverse.

Therefore, angle between ( 6x + 8)° and (7x - 2)° will be equal to ∠2.

∠2 + (6x + 8)° + (7x - 2)° = 180° [ angles at a point on a straight line]

But in this option ∠1 is given in place of ∠2.

Option C is incorrect.

Option D. ∠1 + ∠2 + (7x - 2)° = 180° [sum of all angles in a triangle measure 180°]

(7x - 2)° + ∠2 = 180 - ∠1

(7x - 2)° + ∠2 = 180° - 74°

(7x - 2) + ∠2 = 106°

This option is also correct.

Option C. is the answer.

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Solve for n.<br> 7 + 2n<br> ||<br> =<br> submit

Lunna [17]

Answer:

Step-by-step explanation:

7+2n = 11

2n = 11-7

2n = 4

n = 4/2

therefore n = 2

8 0

1 year ago

Jace is a songwriter who collects royalties in his songs whenever they are played in a commercial or a movie. Jace will earn $50

VashaNatasha [74]

Jace's song were played on 8 commercials and 2 movies

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

<em>Elimination Method</em>
<em>Substitution Method</em>
<em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

<em>Number of Commercials = C</em>

<em>Number of Movies = M</em>

$\texttt{ }$

<em>Jaces songs were played on 6 more commercials than movies.</em>

$\boxed{C = 6 + M}$ → <em>Equation 1</em>

$\texttt{ }$

<em>Jace will earn $50 every time one of his songs is played in a commercial and he will earn $140 every time one of his songs is played in a movie.</em>

<em>His total earnings in the royalties from all commercials and movies was $680.</em>

$\boxed{50C + 140M = 680}$ → <em>Equation 2</em>

$\texttt{ }$

<em>Equation 1 ↔ Equation 2 :</em>

$50C + 140M = 680$

$50 ( 6 + M ) + 140M = 680$

$300 + 50M + 140M = 680$

$190M = 680 - 300$

$190M = 380$

$M = 380 \div 190$

$M = 2$

$\texttt{ }$

$C = 6 + M$

$C = 6 + 2$

$C = 8$

$\texttt{ }$

<h2>Conclusion:</h2>

The number of commercials and the number of movies in which Jaces songs where played is respectively 8 and 2

$\texttt{ }$

<h3>Learn more</h3>

Perimeter of Rectangle : brainly.com/question/12826246
Elimination Method : brainly.com/question/11233927
Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

5 0

3 years ago

What is the likelihood that the children in square 2 will have earlobes that are not attached?

notka56 [123]

Answer : 2/4 children will have earlobes that are not attached

4 0

3 years ago

PLZ help asap i need to help finish this

Levart [38]

Answer:

ok i will

Step-by-step explanation:

pls give me a little bit of time ok

5 0

2 years ago

A new gas- and electric-powered hybrid car has recently hit the market. The distance traveled on 1 gallon of fuel is normally di

Doss [256]

Answer:

a) P [ Z > 70 ] = 0.1075 or 10.75 %

b) P [ Z < 60 ] = 0.1038 or 10.38 %

c) P [ 55 ≤ Z ≤ 70 ] = 0.8882 or 88.82 %

Step-by-step explanation:

Normal Distribution μ = 65 and σ = 4

a) The probability of the car travels more than 70 miles per gallon is:

P [ Z > 70 ] = (Z-μ) ÷ σ ⇒ P [ Z > 70 ] = (70-65) ÷4 P [ Z > 70 ] = 1.25

the point 1.25 corresponds at values, from left tail up to 70 so we must go and look for the area for the point 1.24 which is 0.8925. Then we have the area or probability of all cars traveling up to 70 miles therefore we have to subtract 1 -0,8925

P [ Z > 70 ] = 0.1075 or 10.75 %

b)The probability of the car travels less than 60 miles per gallon is:

P [ Z < 60 ] = ( 60 - μ ) ÷ σ ⇒ P [ Z < 60 ] = (60-65)÷ 4 P [ Z < 60 ] = -1.25

Again -1.25 corresponds to 60 miles per gallon threfore we move to the left and find for point -1.26 which area is 0.1038 so

P [ Z < 60 ] = 0.1038 10.38 %

c) P [ 55 ≤ Z ≤ 70]

For point Z = 70 or 1.25 (case a above) P [ Z ≤ 70] = (70-65)÷4

P [ Z ≤ 70] = 1.25

In this case we got the whole area from the left tail up to 1.25

P [ Z ≤ 70] = 0.8944 (includes the area of the point from the left tail up to the point assocciated to 55 miles and for that reason we have to subtract that area)

P [ Z ≥ 55 ] = (55-65) ÷ 4 P [ Z ≥ 55 ] = -2.5 and the area is 0.0062

So P [ 55 ≤ Z ≤ 70 ] = 0.8944 - 0.0062 = 0.8882

8 0

3 years ago