All categories

3 years ago

Solve pls brainliest

Mathematics

2 answers:

lisabon 2012 [21]3 years ago

7 0

Answer:

18 ft might be the answer

MatroZZZ [7]3 years ago

5 0

Answer:

18 square feet

Step-by-step explanation:

hope this helps :)

You might be interested in

After a power failure, the temperature in a freezer increased at an average rate of 2.5 °F per hour. The total increase was 7.5

makvit [3.9K]

YOU CAN WRITE AN EQUATION OF 7.5 Divide 2.5 = any letter

6 0

3 years ago

8.6E-10 in standard form

Afina-wow [57]

65 is the asnwer hope i helped

6 0

4 years ago

Can some one help me plz??

Hitman42 [59]

The answer is C for this question

5 0

3 years ago

A man shares a $1,200,00 inheritance between his 3 sons in ratio 1: 3: 6. Calculate the difference between the largest share and

soldi70 [24.7K]

A man's inheritance money = $1200

Given :

He shared his inheritance between his 3 sons in the ratio 1:3:6

Then, the money the first son got :

$= \tt \frac{1}{10} \: of \: 1200$

$=\tt \frac{1}{10} \times 1200$

$=\tt \frac{1 \times 120}{10}$

$= \tt \frac{1200}{10}$

$\color{plum} =\tt\$ \: 120$

▪︎Thus, the first son inherited $120.

Money the second son got :

$= \tt \frac{3}{10} \: of \: 1200$

$= \tt \frac{3}{10} \times 1200$

$=\tt \frac{3 \times 1200}{10}$

$= \tt \frac{3600}{10}$

$\color{plum} =\tt \$360$

▪︎Thus, the second son inherited $360.

Money the third son got :

$=\tt \frac{6}{10} \: of \: 1200$

$=\tt \frac{6}{10} \times 1200$

$= \tt \frac{6 \times 1200}{10}$

$= \tt \frac{7200}{10}$

$\color{plum} = \tt\$720$

▪︎Thus, the third son inherited $720.

We know that :

The largest share = $720

The smallest share = $120

Difference between the largest and smallest share :

$= \tt720 - 120$

$\color{hotpink}\tt = 600$

<h3> ●=> Therefore :</h3>

▪︎<em>The difference between the largest and smallest share = 600</em>

7 0

3 years ago

The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota

Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

8 0

3 years ago