Answer:
<h2><em><u>
A to C = 25
</u></em></h2><h2><em><u>
A to B = 13
</u></em></h2><h2><em><u>
C to B = 37
</u></em></h2><h2><em><u>
</u></em></h2>
Step-by-Step Explanation:
<em><u>Perimeter</u></em> = 75
<em><u>Sides:</u></em>
2x + 3
3x + 4
2x - 9
<h2 /><h2><em><u>
1. Equal the sides added together to the perimeter</u></em></h2>
75 = 2x + 3 + 3x + 4 + 2x - 9
<h2><em><u>
2. Simplify Like terms</u></em></h2>
2x + 3 + 3x + 4 + 2x - 9 = 7x - 2
<h2><em><u>
3. Place the equation back together</u></em></h2>
75 = 7x - 2
<h2><em><u>
4. Isolate the variables and numbers</u></em></h2>
75 = 7x - 2
+2 +2
77 = 7x
<h2><em><u>
5. Simplify the equation</u></em></h2>
77 = 7x
/7 /7
<h2><em><u>
11 = x
</u></em></h2>
<h2><em><u>
6. Substitute the value of x into the side lengths.</u></em></h2>
2x + 3 = 2(11) + 3 = 22 + 3 = <em><u>25</u></em>
3x + 4 = 3(11) + 4 = 33 + 4 = <em><u>37</u></em>
2x - 9 = 2(11) - 9 = 22 - 9 = <em><u>13</u></em>
<h3>
Answer: 985</h3>
=============================================
Work Shown:
A = amount after t hours
P = initial amount = 100
r = growth rate in decimal form = 0.10
t = number of hours = 24
--------
A = P*(1+r)^t
A = 100(1+0.10)^24
A = 100*(1.10)^24
A = 100*9.84973267580762
A = 984.973267580762
A = 985
Answer:
7
or -7
Step-by-step explanation:
sqrt(49)
What number multiplied by itself = 49
7*7 = 49
-7*-7 = 49
Answer:
Hello! Your answer is 276
Step-by-step explanation:
Let's just break up the equation:
(3.x2) + (6x45)
6 + 270
<u><em>Hence, the answer is 276</em></u>
<u><em></em></u>
<u><em></em></u>
<u><em></em></u>
<u><em>Hope This Helps :)</em></u>
<u><em>Please mark brainliest</em></u>
Answer:
m∠JKP = 31.5°
Step-by-step explanation:
Incenter of a triangle is the point where all the bisectors of interior angles intersect each other.
JN is the angle bisector of ∠KJL.
Therefore, m∠KJN = m∠LJN
(7x - 6) = (5x + 4)
7x - 5x = 6 + 4
2x = 10
x = 5
m∠KJN = (7x - 6)
= 7(5) - 6
= 35 - 6
= 29°
In ΔKJN,
m∠JKN + m∠KNJ + m∠NJK = 180°
m∠JKN + 90° + 29° = 180°
m∠JKN = 180°- 119° = 61°
Since KO is the angle bisector of ∠JKN,
m∠JKP = 
= 
= 30.5°
