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3 years ago

Polynomial help! 40 pts, please show all work for question 49 part a and b

Mathematics

2 answers:

hoa [83]3 years ago

6 0

Answer:

4x^2 +84x+440

840 in^2

Step-by-step explanation:

The length of the picture and frame is x+ 22+x= 2x+22

The width of the picture and frame is x +20+x = 2x+20

Area is length times width

A = (2x+22) *(2x+20)

We can FOIL to find the area

first 2x*2x = 4x^2

outer 2x*20 =40x

inner 2x*22 = 44x

last = 22*20 = 440

Add these together

4x^2 +40x+44x+440

4x^2 +84x+440

b. x=4

4x^2 +84x+440

4(4)^2 +84(4) +440

4*16 +336+440

64+776

840

Kazeer [188]3 years ago

5 0

Answer:

a) 4x² + 84x + 440

b) 840 in²

Step-by-step explanation:

a) (22 + 2x) × (20 + 2x)

440 + 40x + 44x + 4x²

4x² + 84x + 440

b) x = 4

4(4)² + 84(4) + 440

840 in²

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Convert x2 + y2 -4x = 0 to polar form.

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Answer:

$r(r-4\cos \theta)=0$

Step-by-step explanation:

We are given the following equation:

$x^2 + y^2 -4x = 0$

We have to convert it into polar form.

We put

$x = r \cos \theta\\y = r\sin \theta$

Putting values, we get:

$x^2 + y^2 -4x = 0\\(r\cos \theta)^2 + (r\sin \theta)^2 - 4(r\cos \theta) = 0\\r^2(\cos^2 \theta + \sin^2 \theta) - 4r\cos \theta = 0\\r^2 - 4r\cos \theta = 0\\r(r-4\cos \theta)=0$

is the required polar form.

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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