Question

Polynomial help! 40 pts, please show all work for question 49 part a and b

Answer 1

Answer:

4x^2 +84x+440

840 in^2

Step-by-step explanation:

The length of the picture and frame is x+ 22+x= 2x+22

The width of the picture and frame is x +20+x = 2x+20

Area is length times width

A = (2x+22) *(2x+20)

We can FOIL to find the area

first 2x*2x = 4x^2

outer 2x*20 =40x

inner 2x*22 = 44x

last = 22*20 = 440

Add these together

4x^2 +40x+44x+440

4x^2 +84x+440

b.  x=4

4x^2 +84x+440

4(4)^2 +84(4) +440

4*16 +336+440

64+776

840

Answer 2

Answer:

a) 4x² + 84x + 440

b) 840 in²

Step-by-step explanation:

a) (22 + 2x) × (20 + 2x)

440 + 40x + 44x + 4x²

4x² + 84x + 440

b) x = 4

4(4)² + 84(4) + 440

840 in²