Polynomial help! 40 pts, please show all work for question 49 part a and b
2 answers:
Answer:
4x^2 +84x+440
840 in^2
Step-by-step explanation:
The length of the picture and frame is x+ 22+x= 2x+22
The width of the picture and frame is x +20+x = 2x+20
Area is length times width
A = (2x+22) *(2x+20)
We can FOIL to find the area
first 2x*2x = 4x^2
outer 2x*20 =40x
inner 2x*22 = 44x
last = 22*20 = 440
Add these together
4x^2 +40x+44x+440
4x^2 +84x+440
b. x=4
4x^2 +84x+440
4(4)^2 +84(4) +440
4*16 +336+440
64+776
840
Answer:
a) 4x² + 84x + 440
b) 840 in²
Step-by-step explanation:
a) (22 + 2x) × (20 + 2x)
440 + 40x + 44x + 4x²
4x² + 84x + 440
b) x = 4
4(4)² + 84(4) + 440
840 in²
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y = -6/12 + 7
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Answer:
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