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ozzi
3 years ago
8

How to put -7/9 and -4/9 and 1/9 and 1/2 on a number line from least to greatest

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

-7/9, -4/9, 1/9, 1/2

There's no change as this list is already from smallest to largest

==========================================================

Explanation:

We can get each denominator to 18 as this is the LCD (lowest common denominator)

-7/9 = -14/18 ... multiply top and bottom by 2

-4/9 = -8/18 ... multiply top and bottom by 2

1/9 = 2/18 ... multiply top and bottom by 2

1/2 = 9/18 ... multiply top and bottom by 9

We now have to sort this list {-14/18, -8/18, 2/18, 9/18}

Which is the same as sorting {-14, -8, 2, 9} since we can focus solely on the numerators. This only applies when the denominators are the same.

The list {-14, -8, 2, 9} is already sorted from smallest to largest. Think of a number line. We would have -14 as the left most value, then -8 is next, followed by 2 and then 9.

So the original list of fractions {-7/9, -4/9, 1/9, 1/2} is already sorted from smallest to largest.

--------------

An alternative is to use your calculator to see that

-7/9 = -0.78 approximately

-4/9 = -0.44 approximately

1/9 = 0.11 approximately

1/2 = 0.50

The order from least to greatest is

-0.78, -0.44, 0.11, 0.50

The -0.78 is smaller than -0.44 since its further away from 0

So the order would be

-7/9, -4/9, 1/9, 1/2

and there's no change from the original order your teacher gave you.

WARRIOR [948]3 years ago
4 0

Step-by-step explanation:

Take the LCM of the denominators:

=> LCM = 18

=> -7/9 x 2/2 = -14/18

=> -4/9 x 2/2 = -8/18

=> 1/9 x 2/2 = 2/18

=> 1/2 x 9/9 = 9/18

When the number is negative, the greater the number, the smaller it is.

So, -14 is smaller than -8.

< = smaller than

=> -14/18 < -8/18 < 2/18 < 9/18

=> -7/9 < -4/9 < 1/9 < 1/2

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Check: 1 + 0 + -1 + -2 + -3   =   -2 + -3   =   -5 so 1 is correct.
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A box designer has been charged with the task of determining the surface area of various open boxes (no lid) that can be constru
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Answer:

1) S = 2\cdot w\cdot l - 8\cdot x^{2}, 2) The domain of S is 0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}. The range of S is 0 \leq S \leq 2\cdot w \cdot l, 3) S = 176\,in^{2}, 4) x \approx 4.528\,in, 5) S = 164.830\,in^{2}

Step-by-step explanation:

1) The function of the box is:

S = 2\cdot (w - 2\cdot x)\cdot x + 2\cdot (l-2\cdot x)\cdot x +(w-2\cdot x)\cdot (l-2\cdot x)

S = 2\cdot w\cdot x - 4\cdot x^{2} + 2\cdot l\cdot x - 4\cdot x^{2} + w\cdot l -2\cdot (l + w)\cdot x + l\cdot w

S = 2\cdot (w+l)\cdot x - 8\cdpt x^{2} + 2\cdot w \cdot l - 2\cdot (l+w)\cdot x

S = 2\cdot w\cdot l - 8\cdot x^{2}

2) The maximum cutout is:

2\cdot w \cdot l - 8\cdot x^{2} = 0

w\cdot l - 4\cdot x^{2} = 0

4\cdot x^{2} = w\cdot l

x = \frac{\sqrt{w\cdot l}}{2}

The domain of S is 0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}. The range of S is 0 \leq S \leq 2\cdot w \cdot l

3) The surface area when a 1'' x 1'' square is cut out is:

S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1\,in)^{2}

S = 176\,in^{2}

4) The size is found by solving the following second-order polynomial:

20\,in^{2} = 2 \cdot (8\,in)\cdot (11.5\,in)-8\cdot x^{2}

20\,in^{2} = 184\,in^{2} - 8\cdot x^{2}

8\cdot x^{2} - 164\,in^{2} = 0

x \approx 4.528\,in

5) The equation of the box volume is:

V = (w-2\cdot x)\cdot (l-2\cdot x) \cdot x

V = [w\cdot l -2\cdot (w+l)\cdot x + 4\cdot x^{2}]\cdot x

V = w\cdot l \cdot x - 2\cdot (w+l)\cdot x^{2} + 4\cdot x^{3}

V = (8\,in)\cdot (11.5\,in)\cdot x - 2\cdot (19.5\,in)\cdot x^{2} + 4\cdot x^{3}

V = (92\,in^{2})\cdot x - (39\,in)\cdot x^{2} + 4\cdot x^{3}

The first derivative of the function is:

V' = 92\,in^{2} - (78\,in)\cdot x + 12\cdot x^{2}

The critical points are determined by equalizing the derivative to zero:

12\cdot x^{2}-(78\,in)\cdot x + 92\,in^{2} = 0

x_{1} \approx 4.952\,in

x_{2}\approx 1.548\,in

The second derivative is found afterwards:

V'' = 24\cdot x - 78\,in

After evaluating each critical point, it follows that x_{1} is an absolute minimum and x_{2} is an absolute maximum. Hence, the value of the cutoff so that volume is maximized is:

x \approx 1.548\,in

The surface area of the box is:

S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1.548\,in)^{2}

S = 164.830\,in^{2}

4 0
2 years ago
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