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3 years ago

Can someone help me plz

Mathematics

2 answers:

slega [8]3 years ago

5 0

The answer is the 3rd Choice, A formula. Hope this helps

mihalych1998 [28]3 years ago

3 0

A formula because of google !

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The equation of line m is 3x−5y=−4

vaieri [72.5K]

Slope of this line, -5y = -3x - 4
y = 3/5x + 4/5
So, slope of line which is perpendicular = -5/3 [reciprocal & opposite ]

In short, Your Answer would be -5/3

Hope this helps!

4 0

4 years ago

Which value of x is the solution of the equation 2(x – 4) + 7 = 3? (a) 1 (b) 6 (c) 2 (d) 0

pav-90 [236]

Answer:

Step-by-step explanation:

2(x - 4) + 7 = 3

2x + 2(-4) + 7 = 3

2x - 8 + 7 = 3

2x - 1 = 3

2x - 1 + 1 = 3 + 1

2x = 4

2x/2 = 4/2

x = 2

Hope this helps!!!

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3 years ago

Simplify(1\2)^4 1\16 1\8 1\4

tino4ka555 [31]

Step-by-step explanation:

(1\2)^4 x 1\16 x 1\8 x 1\4 [1/2^4=16]

1/16 x 1/512

=>1/2048

5 0

3 years ago

A LARGE PIZZA AT TONY'S PIZZERIA IS A CIRCLE WITH

AfilCa [17]

You already know what it is cuh

5 0

3 years ago

Read 2 more answers

Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho

Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

$X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )$

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, $P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10$

$P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]$

As, $P(z>1.28)=0.10$ [By z-table]

Then,

$\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712$

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0

4 years ago