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3 years ago

12

Use the tape diagram to answer the following question: 8 is 40% of what number?

1 answer:

Blababa [14]3 years ago

3 0

20 I apologize if this is wrong

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What is 40/6 in simplest form

Rzqust [24]

IT IS 6 2/3 BECAUSE 6 GOES INTO 40 6 TIMES WITH A REMAINDER OF 4. SO, IT IS 6 4/6. YOU GOT TO SIMPLY SO IT IS 6 2/3

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3 years ago

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Evaluate the expression for r = 9.<br><br><br> 19 + r =

tatuchka [14]

Answer:

29

Step-by-step explanation:

because you add 19 and 9

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___ binds oxygen and allows the blood to carry oxygen from the lungs to cells throughout the body.

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Hemoglobin binds oxygen and allows the blood to carry oxygen from the lungs to cells throughout the body. It is a protein that is <span>responsible for transporting oxygen in the blood of vertebrates. Its molecule comprises four subunits, each containing an iron atom bound to a heme group.</span>

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3 years ago

Please help me with this question.

Softa [21]

Answer:

C

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3 years ago

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Suppose we have an urn containing 9 marbles. Two are red, three are green, and four are blue. We randomly select 5 marbles from

Aleonysh [2.5K]

Answer:

probability of selecting 3 green marbles, 1 red marble, and 1 blue marbles

$P(E) =\frac{8}{126} = 0.0634$

Step-by-step explanation:

Given data urn containing '9' marbles

given red marbles = 2

green marbles =3

blue marbles = 4

Five marbles can be selected at a time from '9' marbles in $9_{C_{5} }$ ways

by using formula $n_{C_{r} }=\frac{n!}{(n-r)!r!}$

$9_{C_{5} }=\frac{9!}{(9-5)!5!} = \frac{9X8X7X6X5!}{4!5!}$

After simplification , we get $9_{C_{5} } = 126$

total number of ways n(S) = 126

The probability of selecting '3' green marbles ,one red marble and one blue marble with replacement.

let ' E' be the event of selecting '3' green marbles ,one red marble and one blue marble with replacement.

n(E) = $3_{C_{3} } X2_{C_{1} }X 4_{C_{1} }$ ways

The required probability $P(E) = \frac{n(E)}{n(S)}$

$p(E) = \frac{3_{C_{3} } X2_{C_{1} }X 4_{C_{1} }}{9_{C_{5} } }$

on simplification , we get

$P(E) = \frac{1X2X4}{126} =\frac{8}{126}$

$P(E) =\frac{8}{126} = 0.0634$

7 0

3 years ago