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kirill115 [55]
4 years ago
5

Find the indicated sum. Select your choice and click Submit to check your answer.

Mathematics
1 answer:
Ivahew [28]4 years ago
3 0

Answer:

S_4=50

Step-by-step explanation:

Sum Of Arithmetic Sequence

Given an arithmetic sequence

a_1,\ a_1+r,\ a_1+2r,....,\ a_1+(n-1)r

The sum of the n first terms is

\displaystyle S_n=\frac{(a_1+a_n)n}{2}

Or equivalently

\displaystyle S_n=\frac{[2a_1+(n-1)r]n}{2}

The given sequence is

5, 8, 11 ...

We can see the common difference between terms is r=3

We are asked to find the sum of the terms 2 to 5, it means that

a_1=8, n=4, r=3

\displaystyle S_4=\frac{[2(8)+(4-1)3]4}{2}

\displaystyle S_4=\frac{100}{2}

\boxed{S_4=50}

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If f(x)=5x^2-3 and g(x)=x^2-4x-8, find (f-g)(x)
PSYCHO15rus [73]

Answer:

4x^2 + 4x + 3.

Step-by-step explanation:

(f - g)(x)

= f(x) - g(x)

= 5x^2 - 3 - (x^2 - 4x - 6)

= 5x^2 - 3 - x^2 + 4x + 6

= 4x^2 + 4x + 3.  

7 0
3 years ago
The length of a rectangle is twice its width. Given the length of the diagonal is $5\sqrt{5}$, find the area of the rectangle.
lianna [129]

Answer: Area of rectangle is 50 square units.

Step-by-step explanation:

Since we have given that

Diagonal of the rectangle = 5√5

Let the width of rectangle be 'x'

Let the length of rectangle be '2x'

As we know the formula for diagonal of rectangle:

5\sqrt{5}=\sqrt{l^2+w^2}\\\\(5\sqrt{5}})^2=(2x)^2+x^2\\\\125=4x^2+x62\\\\125=5x^2\\\\\dfrac{125}{5}=x^2\\\\25=x^2\\\\x=\sqrt{25}\\\\x=5\ units

So, Length of rectangle be 2x=2×5=10 units

And the area of the rectangle is given by

Area=Length\times width\\\\Area=10\times 5\\\\Area=50\ sq.\ unit

Hence, area of rectangle is 50 square units.

5 0
3 years ago
In 6 and 7, Find the missing indicated value.
LenKa [72]

Answer:

B.

Step-by-step explanation:

4 0
3 years ago
a. If you select a random sample of 50 ​sessions, what is the probability that the sample mean is between 10.8 and 11.2 ​minutes
natka813 [3]
<span>P stands for probability P(10.8</span>
3 0
3 years ago
Anyone can help me with this
Leokris [45]

Given:

The data values are

11, 12, 10, 7, 9, 18

To find:

The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.

Solution:

We have,

11, 12, 10, 7, 9, 18

Arrange the data values in ascending order.

7, 9, 10, 11, 12, 18

Divide the data in two equal parts.

(7, 9, 10), (11, 12, 18)

Divide each parenthesis in 2 equal parts.

(7), 9, (10), (11), 12, (18)

Now,

Median = \dfrac{10+11}{2}

            = \dfrac{21}{2}

            = 10.5

Lowest value = 7

Greatest value = 18

Lower quartile = 9

Upper quartile = 12

Interquartile range (IQR) = Upper quartile - Lower quartile

                                        = 12 - 9

                                        = 3

Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.

8 0
3 years ago
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