Simplify the given exponential expression.
2 answers:
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The parabola will show the vertex in the format: y-k = (x-h)^2, where the vertex point
lies at (h, k).
let's first put it in "y =" standard format:
Since we cannot get a perfect square out of this, we complete the square: a=1, b=2, c=3
(b/2)^2 = (2/2)^2 = 1, so
So there's +2 leftover, since 3-1=2; so:
Now we'll subtract the 2 from both sides to show our vertex:
where our vertex (h, k) is at (-1, 2)
lies at (h, k).
let's first put it in "y =" standard format:
Since we cannot get a perfect square out of this, we complete the square: a=1, b=2, c=3
(b/2)^2 = (2/2)^2 = 1, so
So there's +2 leftover, since 3-1=2; so:
Now we'll subtract the 2 from both sides to show our vertex:
where our vertex (h, k) is at (-1, 2)
Answer:
The constant of variation is $1.50
Step-by-step explanation:
Given
Point 1 (1,2)
Point 2 (5,8)
Required
Constant of Variation
Though the graph would have assisted in answering the question; its unavailability doesn't mean the question cannot be solved.
Having said that,
the constant variation can be solved by calculating the gradient of the graph;
The gradient is often represented by m and is calculated as thus
Where
By substituting values for x1,x2,y1 and y2; the gradient becomes
Hence, the constant of variation is $1.50