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MAXImum [283]
3 years ago
5

On a standardized exam, the scores are normally distributed with a mean of 135 and a

Mathematics
1 answer:
labwork [276]3 years ago
3 0

Answer:

-1

Step-by-step explanation:

mean, mu = 135.

Standard deviation = 20

X = 115

use the z score formula : z = \frac{x-mu}{standard deviation}

to get (115-135)/20 = -1

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Reggie drove his race car 4 times around the track for a total of 10 miles. How many kilometers did he drive? (Note that 1 mile
Allushta [10]

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16.1 km

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A discounted ticket for a football game costs $12.50 less than the original price.you pay $63 for a discounted ticket
Tanya [424]

Answer:

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4 0
3 years ago
Find the measure of the three missing angles in the parallelogram below.
elixir [45]

Answer: x = 77 degrees, y = 77 degrees, z = 103 degrees

Step-by-step explanation:

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4 0
2 years ago
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Find an equation of the line having slope -2 that passes through the point (1, 5)
Alenkasestr [34]
Slope of -2, (1,5)

y = mx + b
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now we sub and find b, the y int
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so ur equation is : y = -2x + 7

The approximation method used to estimate a point between 2 given points is called linear interpolation. The approximation method used to estimate a point that does not lie between 2 given points is called linear extrapolation.A linear function has the form f(x) = mx + b. Its graph is a line that has slope m and y intercept at (0,b).

8 0
3 years ago
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Solve this query plzzz​
Olin [163]

Step-by-step explanation:

\frac{\sin \:4A}{\cos \:2A}  \times \frac{1 - \cos \:2A}{1 - \cos\:4A}   = \tan \:A \\  \\ LHS =  \frac{\sin \:4A}{\cos \:2A}  \times \frac{1 - \cos \:2A}{1 - \cos\:4A}   \\  \\  =  \frac{2\sin \:2A.\cos \:2A}{\cos \:2A}   \times  \frac{1 - (2 { \cos}^{2}A - 1) }{1 - (2 { \cos}^{2}2A - 1) } \\  \\  = 2\sin \:2A   \times  \frac{1 - 2 { \cos}^{2}A  +  1}{1 - 2 { \cos}^{2}2A  + 1 } \\  \\  = 2\sin \:2A   \times  \frac{2- 2 { \cos}^{2}A  }{2 - 2 { \cos}^{2}2A   } \\  \\   = 2\sin \:2A   \times  \frac{2(1 - { \cos}^{2}A)  }{2 (1-  { \cos}^{2}2A)   } \\  \\   = 2\sin \:2A   \times  \frac{1 - { \cos}^{2}A}{1-  { \cos}^{2}2A   } \\  \\     = 2\sin \:2A   \times  \frac{ { \sin}^{2}A}{{ \sin}^{2}2A   } \\  \\    = 2  \times  \frac{ { \sin}^{2}A}{{ \sin}2A   } \\  \\   = 2  \times  \frac{ { \sin}^{2}A}{{ 2\sin}A. \cos \:   A } \\  \\   = \frac{ { \sin}A}{ \cos \:   A }  \\  \\  = tan \: A \\  \\  = RHS \\

7 0
4 years ago
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