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Butoxors [25]
2 years ago
15

Can someone find the error ?? And solve it Please this geometry Specials right triangle

Mathematics
2 answers:
Nuetrik [128]2 years ago
8 0

In a 30-60-90 triangle the hypotenuse is 2 times the shortest leg.

In the problem, they multiplied the shortest leg by sqrt(3)

Hypotenuse = shortest leg x 2

Hypotenuse = 7 x 2 = 14 units

jek_recluse [69]2 years ago
5 0

Answer:

the error is not there

Step-by-step explanation:

What is the difference between a bystander who does nothing and a perpetrator that causes harm to someone or something?

What is the difference between a bystander who does nothing and a perpetrator that causes harm to someone or something?

What is the difference between a bystander who does nothing and a perpetrator that causes harm to someone or something?

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Please help this is pre algebra :)
larisa [96]

Step-by-step explanation:

the explanaition of the answer and solution is in the picture, check it out. this is for question 14

3 0
3 years ago
(a+b)2 ;a=1/2 and b=2
FrozenT [24]

Answer:

\frac{25}{4}

Step-by-step explanation:

a + b = \frac{1}{2} + 2 = 2 \frac{1}{2} = \frac{5}{2}, thus

(a + b)² = (\frac{5}{2} )² = \frac{5}{2} × \frac{5}{2} = \frac{5(5)}{2(2)} = \frac{25}{4}

8 0
3 years ago
Read 2 more answers
A linear function is written:<br> f(x) = 3/2x-4<br> What is the value of f(5)?
valentinak56 [21]

Answer:

f(5)=3.5

Step-by-step explanation:

f(x)=\frac{3}{2}x-4\\f(5)=\frac{3}{2}(5)-4\\f(5)=7.5-4\\f(5)=3.5

Hope this helped!! Have an amazing day :D

4 0
3 years ago
When is g(x) = 0 for the function g(x) = 5⋅2^3x + 4?
SashulF [63]
The answer should be when X=1
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6 0
3 years ago
If there are 6 serving in a 2/3 pound lb package of pound is in each serving
Serhud [2]

Answer:

\boxed{\math{\frac{1}{9}\text{ lb}}}

Step-by-step explanation:

\text{Size of one serving} = \dfrac{\text{Total size}}{\text{No of servings}} = \dfrac{\frac{2}{3}\text{ lb}}{\text{6 servings}}\\\\\text{Change the 6 to a fraction and change divide to multiply}\\\\\dfrac{2}{3} \div 6 = \dfrac{2}{3} \times \dfrac{1}{6}

\text{Cancel the 2s}\\\\\dfrac{2}{3} \times \dfrac{1}{6} = \dfrac{1}{3} \times \dfrac{1}{3}\\\\\text{Multiply numerators and denominators}\\\\\dfrac{1}{3} \times \dfrac{1}{3} = \dfrac{1}{9}\\\\\text{Each serving contains }\boxed{\mathbf{\frac{1}{9}\textbf{ lb}}}

3 0
3 years ago
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