We need to define our outcomes and events.
Finding the probability<span> of each event occurring
separately, and then multiplying the probabilities is the step to <span>finding
the probability</span> of two
independent events that occur in
sequence.
</span>
<span>
To solve this problem, we take note of this:</span>
The roll of the two dice are denoted by the pair
(I, j) ∈ S={ (1, 1),(1, 2),..., (6,6) }
Each pair is an outcome. There are 36 pairs and each has
probability 1/36. The event “doubles” is { (1, 1),(2, 2)(6, 6) } has
probability p= 6/36 = 1/6. If we define ”doubles” as a successful roll, the
number of rolls N until we observe doubles is a geometric (p) random variable
and has expected value E[N] = 1/p = 6.
Answer:
ADD THE TEN PERCENT IT WOULD BE 418.82
Step-by-step explanation:
ADDDDDDDDDDDDDDDDDDDD
Answer:
d=−bc+a/0.5bc
Step-by-step explanation:
Let's solve for d.
a=0.5bcd+bc
Step 1: Flip the equation.
0.5bcd+bc=a
Step 2: Add -bc to both sides.
0.5bcd+bc+−bc=a+−bc
0.5bcd=−bc+a
Step 3: Divide both sides by 0.5bc.
0.5bcd/0.5bc = −bc+a/0.5bc
d=−bc+a/0.5bc
Answer:
D
Step-by-step explanation:
p +/- [z + sqrt(pq/n)]
0.65 + [1.645 × sqrt[0.65 × (1-0.65) ÷ 50]
0.65 +/- 0 1109613165
[0.5390386835 , 0.7609613165]
Three and more points are collinear
