Answer:
x=4 and y=2
Step-by-step explanation:
Answer:
1/3x - 1/3
Step-by-step explanation:
First off, we can write this the words as a mathematical equations so its easier to work with:
1/3 (x - 1)
Now we can use distributive property and finally simplify this equation:
1/3 (x-1)
1/3x - 1/3 x 1
1/3x - 1/3
Step-by-step explanation:
Area =0.5×base×height
Area= 0.5×5×3=7.5ft
Answer:
1330.808 euros
Step-by-step explanation:
Let's first calculate the total amount of kilograms,
for the first 60, we have to:
50 kg
4 hg = 0.5 kg
60 dag = 0.6
5 g = 0.005 kg
adding: 50 + 0.5 +0.6 + 0.005 = 51.105 kg per tree, but they are 60
51.105 * 60 = 3066.3
now for the other 20:
53 kg
2 hg = 0.2 kg
16 dag = 0.16
5 g = 0.005
adding: 53 + 0.2 +0.16 + 0.005 = 53.365 kg per tree, but they are 20
53,365 * 20 = 1067.3
in total it would be: 3066.3 + 1067.3 = 4133.6
they tell us that 1/5 is the quantity in liters:
4133.6 * 1/5 = 826.72 liters
so to calculate the earnings it would be:
2.65 * 826.72 - 860 = 1330.808
which means that in net earnings are 1330.808 euross
Answer:
Step-by-step explanation:
1. Approach
Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.
2. Solve for the width
It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.
Substitute,
Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.
Inverse operations,
3. Solve for the area
Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).
Substitute,