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Pavel [41]
3 years ago
13

Answer the question right you get brainliest

Mathematics
1 answer:
azamat3 years ago
7 0

Answer:

radius is 25

hope thus helps

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Which is the result when the equation y = -2/5x + 5/2 is converted to<br> standard form?
mixer [17]

Answer:

 4x+10y-25=0

Step-by-step explanation:

y=-\frac{2}{5} x+\frac{5}{2}

Multiply by 10 on both sides,

10y=-4x+25\\

so 4x+10y-25=0

4 0
2 years ago
Read 2 more answers
What is the diameter and radius also the area
serious [3.7K]
Radius-24, diameter-48, area-1809.56
6 0
4 years ago
Determine the equation of the line that is perpendicular to the lines r(t)=(-2+3t,2t,3t)
Mnenie [13.5K]
<span>Vector Equation
(Line)</span>(x,y) = (x,y) + t(a,b);tERParametric Formx = x + t(a), y = y + t(b); tERr = (-4,-2) + t((-3,5);tERFind the vector equation of the line passing through A(-4,-2) & parallel to m = (-3,5)<span>Point: (2,5)
Create a direction vector: AB = (-1 - 2, 4 - 5) 
= (-3,-1) or (3,1)when -1 (or any scalar multiple) is divided out.
r = (2,5) + t(-3,-1);tER</span>Find the vector equation of the line passing through A(2,5) & B(-1,4)<span>x = 4 - 3t
y = -2 + 5t
;tER</span>Write the parametric equations of the line passing through the line passing through the point A(4,-2) & with a direction vector of m =(-3,5)<span>Create Vector Equation first:
AB = (2,8)
Point: (4,-3)
r = (4,-3) + (2,8); tER
x = 4 + 2t 
y = -3 + 8t
;tER</span>Write the parametric equations of the line through A(4,-3) & B(6,5)<span>Make parametric equations: 
x = 5 + 4t
y = -2 + 3t ; tER
For x sub in -3
-3 = 5 + 4t 
(-8 - 5)/4 = t
-2 = t
For y sub in -8 
-8 = -2 + 3t
(-8 + 2)/3 = t
-2 = t
Parameter 't' is consistent so pt(-3,-8) is on the line.</span>Given the equation r = (5,-2) + t(4,3);tER, is (-3,-8) on the line?<span>Make parametric equations: 
x = 5 + 4t
y = -2 + 3t ; tER
For x sub in 1
-1 = 5 + 4t 
(-1 - 5)/4 = t
-1 = t
For y sub in -7 
-7 = -2 + 3t
(-7 + 2)/3 = t
-5/3 = t
Parameter 't' is inconsistent so pt(1,-7) is not on the line.</span>Given the equation r = (5,-2) + t(4,3);tER, is (1,-7) on the line?<span>Use parametric equations when generating points: 
x = 5 + 4t
y = -2 + 3t ;tER
X-int:
sub in y = 0
0 = -2 + 3t
solve for t
2/3 = t (this is the parameter that will generate the x-int) 
Sub t = 2/3 into x = 5 + 4t 
x = 5 + 4(2/3)
x = 5 + (8/3)
x = 15/3 + (8/3) 
x = 23/3
The x-int is (23/3, 0)</span>What is the x-int of the line r = (5,-2) + t(4,3); tER?Note: if they define the same line: 1) Are their direction vectors scalar multiples? 2) Check the point of one equation in the other equation (LS = RS if point is subbed in)What are the two requirements for 2 lines to define the same line?
3 0
4 years ago
<img src="https://tex.z-dn.net/?f=50.705%20%5Cdiv%202.646" id="TexFormula1" title="50.705 \div 2.646" alt="50.705 \div 2.646" al
nikitadnepr [17]

Answer:

19.1628873772

Step-by-step explanation:

50.70500 ÷ 2.64600 = 19.1628873772

8 0
3 years ago
Read 2 more answers
Find the Hight of a cylinder surface area is 980.18cm^2 and radius is 6 cm
KATRIN_1 [288]

Hope you could understand.

If you have any query, feel free to ask.

3 0
2 years ago
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