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liraira [26]
3 years ago
10

B R O H E L P M E T H A N K Y O U : < )

Mathematics
1 answer:
Ksivusya [100]3 years ago
4 0
Rules: (-) plus (-) equals positive.
Anything negative in absolute value will turn positive. Example, | -2 | —> 2

|-4b-8|+|-1 -b^2| +2b^3; b=-2

First step is substituting all the “b” to -2.
|-4(-2) -8| + |-1 -(-2)^2| +2(-2)^3
Then start solving.
|8-8| + |-1 -(4)| +2(-8)
|0| + |-5| -16
0 +5 -16= -11
Answer: -11
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A + (b + c) = (A + b) + c<br><br><br> What property is this equation
Free_Kalibri [48]

Answer:

Step-by-step explanation:

Associative property

7 0
3 years ago
Suppose that the length of a side of a cube X is uniformly distributed in the interval 9
Nastasia [14]

Answer:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

Step-by-step explanation:

Given

9 < x < 10 --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

v = x^3

For a uniform distribution, we have:

x \to U(a,b)

and

f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.

9 < x < 10 implies that:

(a,b) = (9,10)

So, we have:

f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Solve

f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Recall that:

v = x^3

Make x the subject

x = v^\frac{1}{3}

So, the cumulative density is:

F(x) = P(x < v^\frac{1}{3})

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right. becomes

f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.

The CDF is:

F(x) = \int\limits^{v^\frac{1}{3}}_9 1\  dx

Integrate

F(x) = [v]\limits^{v^\frac{1}{3}}_9

Expand

F(x) = v^\frac{1}{3} - 9

The density function of the volume F(v) is:

F(v) = F'(x)

Differentiate F(x) to give:

F(x) = v^\frac{1}{3} - 9

F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}

F'(x) = \frac{1}{3}v^{-\frac{2}{3}}

F(v) = \frac{1}{3}v^{-\frac{2}{3}}

So:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

8 0
2 years ago
HELP IM USING ALL MY POINTS
Romashka-Z-Leto [24]

Answer:

5 days

Step-by-step explanation:

If you write it out it will look like this 8 1/2÷1 7/10

since you can't divide mixed fractions very easily, you make them improper fractions. 8 1/2 -> 17/2    1 7/10 -> 17/10

So it looks like 17/2÷17/10

because of maths you have to turn 17/10 into 10/17

And when you do the maths (multiply it together) you get 5

5 0
2 years ago
Read 2 more answers
the price of an article is Marked 25% above the cost price .if it is solid the profit of Rs.500 after allowing 15% discount .wha
gavmur [86]

Answer:

  Rs 8500

Step-by-step explanation:

For a cost price of c, the marked price is ...

  marked = c +25%·c = 1.25c

After the 15% discount, the sale price will be ...

  s = marked -15%·marked = 0.85·marked = (0.85)(1.25c) = 1.0625c

The profit will be the difference between the sale price s and the cost c:

  p = s -c

  500 = (1.0625c) -c = 0.0625c

Then the cost is ...

  500/0.0625 = c = 8000

and the sale price is ...

  s = c +p = 8000 +500 = 8500 . . . rupees

The selling price will be Rs 8500.

8 0
2 years ago
The radius of the circle is 100 mm what is the diameter
Illusion [34]

Answer:

The answer is B) 200mm. Check the image for the workings

7 0
2 years ago
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