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sergiy2304 [10]
3 years ago
10

3f + 9 < 21 Help please

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
6 0

Answer:

\boxed {f < 4}

Step-by-step explanation:

Solve the following inequality:

3f + 9 < 21

-Subtract 9 on both sides:

3f + 9 - 9 < 21 - 9

3f < 12

-Divide both sides by 3:

\frac{3f}{3} < \frac{12}{3}

\boxed {f < 4}

fiasKO [112]3 years ago
4 0

Answer:

f < 4

Step-by-step explanation:

3f + 9 < 21

21 - 9 = 12

12 / 3 = 4

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The proportion of students who own a cell phone on college campuses across the country has increased tremendously over the past
galina1969 [7]

Complete Question

The complete question is shown on the uploaded image  

Answer:

1 ) The correct option B

2) The correct option is  C

3)  The correct option is  C

4)  The correct option is  C

Step-by-step explanation:

From the question we are told that

   The proportion that own a cell phone  is  p = 0.90

    The  sample  size is  n =  15

Generally the appropriate distribution for X is mathematically  represented as

      X  \ is  \ B( n , p )

So  

       X  \ is  \ B( 15 , 0.90 )

Generally the number students that  own a cell phone in a simple random sample of 15 students is mathematically represented as

              \mu  =  n  *  p

              \mu  =  15 *  0.90

              \mu  =   13.5

Generally the standard deviation of the number of students who own a cell phone in a simple random sample of 15 students is mathematically represented as

                \sigma  =  \sqrt{ n *  p *  q }

Where  q is mathematically evaluated as

          q =  1- p

           q =  1- 0.90

           q =  0.10

            \sigma  =  \sqrt{ 15 *  0.90 *  0.10 }

            \sigma  = 1.16

Generally the probability that all students in a simple random sample of 15 students own a cell phone is mathematically represented as

   P(X =  15) =  \left 15} \atop {}} \right.C_{15} *  p^{15} *  q^{15 - 15}    

     P(X =  15) =  \left 15} \atop {}} \right.C_{15} *  (0.90)^{15} *  (0.10 )^{15 - 15}

From the combination calculator  is      \left 15} \atop {}} \right.C_{15} =  1

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PtichkaEL [24]

You can find the slope either by just looking at the line or using the slope formula.

#1: The slope formula is:

m=\frac{y_2-y_1}{x_2-x_1}       Find two points and plug it into the formula

I will use (0, 2) and (1, -1)

(0, 2) = (x₁, y₁)

(1, -1) = (x₂, y₂)

m = \frac{y_2-y_1}{x_2-x_1}

m = \frac{2-(-1)}{0-1}   [two negatives cancel each other out and become positive]

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#2: To find the slope without having to do the work, you use this:

m=\frac{rise}{run}

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Run is the number of units you go to the right from each point

If we start at a defined/obvious point, like (0, 2), find the next point and see how many units it goes up or down and to the right. The next point is (1, -1), so from each point, you go down 3 units and to the right 1 unit. So your slope is -3/1 or -3. You can make sure the slope is right by looking at another point.

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Answer: 13.85kg Hope this helps, please consider making me Brainliest.

Step-by-step explanation:

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irina [24]

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