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frosja888 [35]
3 years ago
15

There are 176 freshmen and 18 adults, going on a trip to Great Adventure. The tickets are $60.00 for an individual or $300.00 fo

r up to a group of 10 people. If your school purchased a combination of group and individual tickets, how much money is needed?
Mathematics
1 answer:
Iteru [2.4K]3 years ago
7 0

Answer:

$5940

Step-by-step explanation:

19 groups = 19 x 300 = $5700

4 extra tickets = 4 x 60 = $240

$5700 + $240 = $5940

Total people going = 194

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Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

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3 years ago
In order to set premiums at profitable levels, insurance companies must estimate how much they will have to pay in claims on car
Alex73 [517]

I hope someone sloves your problem :)

8 0
3 years ago
The function h(t)=−16t2+7t+63 represents the height of a t-shirt launched from a t-shirt cannon after t seconds. a. Write an equ
Fittoniya [83]

Answer:

(a)\ -16t^2 + 7t + 63=0

(b)\ t = 2.215

Step-by-step explanation:

Given

h(t) = -16t^2 + 7t + 63

Solving (a): Equation when it hits the ground.

This means that h(t) = 0

So, we have:

h(t) = -16t^2 + 7t + 63

-16t^2 + 7t + 63=0

Solving (b): The value of t in (a)

-16t^2 + 7t + 63=0

Using quadratic formula, we have:

t = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

This gives:

t = \frac{-7 \± \sqrt{7^2 - 4*-16*63}}{2*-16}

t = \frac{-7 \± \sqrt{49+ 4032}}{2*-16}

t = \frac{-7 \± \sqrt{4081}}{-32}

t = \frac{-7 \± 63.88}{-32}

Split

t = \frac{-7 + 63.88}{-32}; or\ t = \frac{-7 - 63.88}{-32}

t = \frac{56.88}{-32}; or\ t = \frac{-70.88}{-32}

t = -1.7775; or\ t = 2.215

Time can't be negative; So:

t = 2.215

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3 years ago
4 – 3m<br><br> PLS HELP SOMEONE
Natalka [10]

Answer: it's 1 :)

Step-by-step explanation:

8 0
2 years ago
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A toy rocket is launched from the ground straight upward. The height of the rocket above the ground, in feet, is given by the eq
Oksanka [162]

Answer:

Although strictly speaking of mathematics i.e. theoritically,  

t

can take any value from  

{ − ∞ , ∞ ] ,

however, it is essentially a physical problem related to Physics and we cannot have negative  

t  i.e.  t ≥ 0

Further, after the maximum is reached at  t = 2  (observe that first differential is  h ' ( t ) = − 32 t + 64 , which is zero at  t = 2  and second derivative  h ' ' ( t ) = − 32  is negative and at this we have  h ( 2 ) = 64 ), at  t = 4 ,  h ( 4 ) = 0  i.e. toy rocket falls back to the ground and as such, we cannot have  h > 4 .

Hence, domain for  t  is  [ 0 , 4 ] .

tbh google

8 0
3 years ago
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