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4 years ago

11. The scale for a drawing of the tennis court is

Mathematics

1 answer:

Ivenika [448]4 years ago

3 0

Answer:

I believe the correct answer would be 220 meters.

Step-by-step explanation:

If one centimeter equals 2 meters, then you would have to multiply the width (5.5 cm.) by 2 and the length (10 cm.) by 2. After you multiply those, you get 11 meters for the width and 20 meters for the length. You then multiply those by each other, so 11x20, and you get 220.

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How do you write this statement as a equation? 2 more than 3 times a number is 17

evablogger [386]

5 times n=17 because you have to use algebra

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Which pair of ratios form a proportion?

leva [86]

Answer:

D: 5 : 8 and 20 : 32

Step-by-step explanation:

A is incorrect because 3 x 1.33 = 4 and 4 x 1.25 = 5.

B is incorrect because 10 x 1.6 = 16 and 12 x 1.5 = 18.

C is incorrect because 7 x 1.428 = 10 and 10 x 1.4 = 14.

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3 years ago

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A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3>Solution:</h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

The area of rectangle is given as:

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

General form of quadratic equation is

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

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3 years ago

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EastWind [94]

Answer:

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Step-by-step explanation:

To evaluate f(8) substitute x = 8 into f(x)

f(8) = - 2(8) + 9 = - 16 + 9 = - 7

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g(- 1) = (- 1)² - 2 = 1 - 2 = - 1

Then

f(8) + g(- 1) = - 7 + (- 1) = - 7 - 1 = - 8

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3 years ago