Simplify the following:
((8 x^3 y^2 a^2 b^4)/4)^(-2)
8/4 = (4×2)/4 = 2:
(2 x^3 y^2 a^2 b^4)^(-2)
Multiply each exponent in 2 x^3 y^2 a^2 b^4 by -2:
(x^(-2×3) y^(-2×2) a^(-2×2) b^(-2×4))/(2^2)
-2×3 = -6:
(x^(-6) y^(-2×2) a^(-2×2) b^(-2×4))/2^2
-2×2 = -4:
(y^(-4) a^(-2×2) b^(-2×4))/(2^2 x^6)
-2×2 = -4:
(a^(-4) b^(-2×4))/(2^2 x^6 y^4)
-2×4 = -8:
b^(-8)/(2^2 x^6 y^4 a^4)
2^2 = 4:
Answer: 1/(4 x^6 y^4 a^4 b^8) thus the answer is A
Y/3.5= 25
(Hoped this help^)
You need to prove that <A = <E
since c is the midpoint of line AE then AC = EC
i dont remember the name of the theroem that states that when a triangle has two sides and an angle in common that it is congruent i think it called SAS congruence therom. use that to prove that the <| s are congruent then use CPCTC to prove that <A = <E. then prove that they are || by usint the int angle therom.
Answer:
A
Step-by-step explanation:
Calculate the slope m using the slope formula
m = 
with (x₁, y₁ ) = (6, a ) and (x₂, y₂ ) = (9, - 4 )
m = 
= 
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
2x - 3y = 6 ( subtract 2x from both sides )
- 3y = - 2x + 6 ( divide through by - 3 )
y = 
x - 2 ← in slope- intercept form
with slope m =
Parallel lines have equal slopes , then
= , so
- 4 - a = 2 ( add 4 to both sides )
-a = 6 ( multiply both sides by - 1 )
a = - 6 → A
