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3 years ago

Finding the perimeter or area of a rectangle given one of th

Mathematics

1 answer:

babymother [125]3 years ago

3 0

Answer:

<h3>The answer is 70cm</h3>

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

Area of a rectangle = l × w

where

l is the length

w is the width

From the question

The length of a rectangle six times its width which is written as

l = 6w

Area = 150cm²

Substitute these values into the formula for finding the area

That's

150 = 6w²

Divide both sides by 6

w² = 25

Find the square root of both sides

width = 5cm

Substitute this value into l = 6w

That's

l = 6(5)

length = 30cm

So the perimeter of the rectangle is

2(30) + 2(5)

= 60 + 10

Hope this helps you

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3 years ago

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lys-0071 [83]

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3 years ago

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diamong [38]

c² = n²

√c² = √n²

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3 years ago

Read 2 more answers

Help i want to know what is 5m and 10m in feet and explain if you can

tatyana61 [14]

Well, to start with, 1 meter = 3 feet.
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3 years ago

Can you help meee get this ?

nikdorinn [45]

Answer: y=4/5x-2 or y=4/5x+(-2)

Step-by-step explanation:

The formula for slope-intercept form is y=mx+b.

To find the slope, we can use the formula $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ and plugging in the points given.

$m=\frac{6-2}{10-5} =\frac{4}{5}$

We know our slope is 4/5. We can plug this into our slope-intercept form and then plug in a point to find b, y-intercept.

$y=\frac{4}{5} x+b$

$2=\frac{4}{5}(5)+b$

$2=4+b$

$b=-2$

We know the y-intercept is -2.

THe final equation is y=4/5x-2 or y=4/5x+(-2).

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3 years ago