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solong [7]
3 years ago
9

You have 16 digs for your current volleyball season. There are 3 games left in the season. You want to break your previous recor

d of 20 digs in a
season. Write and solve an inequality that represents the number of digs you must get in the remaining 3 games to break your record
Mathematics
1 answer:
g100num [7]3 years ago
3 0

Answer:

we must get more than 4 digs in the remaining 3 games break record of 20

Step-by-step explanation:

given data

current volleyball season = 16 digs

games left in the season = 3

previous record = 20 digs

solution

we consider here the number of digs  x that must get in the remaining 3 games to break your record

so for break  previous record of 20 digs, we have to get more than 20  

so 16 digs must add to x to greater than 20

x + 16  ≥ 20   ...............................1

so x will be

x ≥ 20 - 16

x ≥ 4  

so that we must get more than 4 digs in the remaining 3 games break record of 20

You might be interested in
Let n1equals50​, Upper X 1equals30​, n2equals50​, and Upper X 2equals10. Complete parts​ (a) and​ (b) below. a. At the 0.05 leve
Viefleur [7K]

Answer:

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.

Step-by-step explanation:

1) Data given and notation  

X_{1}=30 represent the number of people with a characteristic in 1

X_{2}=10 represent the number of people with a characteristic in 2

n_{1}=50 sample of 1 selected  

n_{2}=50 sample of 2 selected  

p_{1}=\frac{30}{50}=0.6 represent the proportion of people with a characteristic in 1

p_{2}=\frac{10}{50}=0.2 represent the proportion of people with a characteristic in 2

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportion 1 is different from proportion 2 , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{30+10}{50+50}=0.4  

3) Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

4) Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.    

Since is a two sided test the p value would be:  

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.  

3 0
3 years ago
Given the function f(x) = 4x - 2, explain and show how to find the average rate of change between x = 2 and x = 4.
zalisa [80]

Answer:

The average rate of change between x = 2 and x = 4 is of 4.

Step-by-step explanation:

Average rate of change:

The average rate of change of a function f(x) in an interval [a,b] is given by:

A = \frac{f(b)-f(a)}{b-a}

In this question:

f(x) = 4x - 2, b = 4, a = 2

Thus:

f(b) = f(4) = 4(4) - 2 = 16 - 2 = 14

f(a) = f(2) = 4(2) - 2 = 8 - 2 = 6

Average rate of change:

A = \frac{f(b)-f(a)}{b-a}

A = \frac{14-6}{4-2}

A = \frac{8}{2}

A = 4

The average rate of change between x = 2 and x = 4 is of 4.

7 0
3 years ago
Why is the equation y-y1=m(x-x1) called the point-slope form?
MatroZZZ [7]

Answer:

The equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

Step-by-step explanation:

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

The formula y-y_1=m\left(x-x_1\right) is termed as the point-slope form of the line equation because if we know one point on a certain line and the slope of that line, then we can easily get the line equation with this formula and, hence, determine all other points on the line.

For example, if we are given the point (1, 1) and slope m = 2

Then substituting the values m = 2 and the point (1, 2)

y-y_1=m\left(x-x_1\right)

y - 2 = 2(x-1)

y - 2 = 2x-2

y = 2x-2+2

y = 2x

Therefore, the equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

5 0
2 years ago
Soni rent Anju a sum of Rs 40,000 at the rate of 2 paisa per 2 rupees per
galben [10]

Answer:

RS 14400

Step-by-step explanation:

Given the following :

Principal sum = RS 40000

Rate = 2 paisa per 2 rupee per month

Interest at the end of 3 years

1 rupee = 100 paisa

2 Paisa per 2 rupee per month :

2/200 per month = 1 / 100 per month,

Hence rate = 0.01 = 1% monthly

Annual rate = 1% × 12 = 12 % = 0.12

Simple interest :

Principal × rate × time

40000 × 0.12 × 3

40000 × 0.36

= RS 14,400

3 0
3 years ago
An employer uses the linear regression equation y = 0.18 x + 320.22 to predict the weekly salary, y, of an employee who sells x
Nata [24]

Answer:

Option C is correct.

Alex earned about $60 more than Joaquin did.

Step-by-step explanation:

The linear regression equation

y = 0.18 x + 320.22

is used to predict the weekly salary, y, of an employee who sells x dollars worth of merchandise.

Joaquin sold $1500 worth of goods. Meaning that x for that week for Joaquin is 1500.

Joaquin' s salary for that week is then given as

y = 0.18x + 320.22

y = 0.18(1500) + 320.22 = 590.22

Hence, Joaquin's salary for that week = $590.22

Alex earns $650 that week. Meaning that y for Alex in that week = 650

y = 0.18x + 320.22

650 = 0.18x + 320.22

0.18x = 650 - 320.22 = 329.78

x = (329.78/0.18) = 1832.1

Hence, Alex sold goods worth $1832.1 that week.

Joaquin sold goods worth $1500

Joaquin earned $590.22

Alex sold goods worth $1832.1

Alex earned $650

From this calculation, it is evident that 'Alex earned about $60 more than Joaquin did' is the correct option as $650 is about $60 more than $590.22

Hope this Helps!!!

7 0
3 years ago
Read 2 more answers
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