3x+2y=11
y=5x-1
Substitute the y in the first equation:
3x+2(5x-1)=11
y=5x-1
3x+10x-2=11
y=5x-1
13x=13
y=5x-1
Now substitute the x to find the y:
x=1
y=5-1=4
Let u = 5x+1. Then du = 5·dx, and your integral is

Answer:
2
Step-by-step explanation:
You set up and equation:
5+6x = 17
You solve it and get 2.
Answer:
hmm
Step-by-step explanation:
Answer:
A. m(-1)^(n-1)
Step-by-step explanation:
The degree of m doesn't change so none of the expressions with n as an exponent of m can possibly be correct. That leaves only choice A.
_____
You will find that when alternating signs are required, the term (-1)^n will be a factor. An offset of ±1 can be added to the n to make the initial sign be what you want. Here we want +1 for n=1, so an exponent of (n-1) is appropriate.