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mina [271]
2 years ago
12

Solve the quadratic equation by completing the square. x^2+2x-2=0

Mathematics
1 answer:
astraxan [27]2 years ago
5 0

The solution to the quadratic equation by completing the square is x = -1 + √3, x = -1 - √3

<h3>What is a quadratic equation?</h3>

Any equation of the form \rm ax^2+bx+c=0  where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}

We have a quadratic equation:

x² + 2x - 2 = 0

x² + 2x + 1 - 1 - 2 = 0

(x + 1)² - 3 = 0

(x + 1)² = 3

x + 1 = ± √3

x = -1 ± √3

Thus, the solution to the quadratic equation by completing the square is x = -1 + √3, x = -1 - √3

Learn more about quadratic equations here:

brainly.com/question/2263981


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Will give brainliest!<br><br> N/2+25 = 375 <br><br> N = ? <br><br> (n/2 is a fraction)
Art [367]

Solve for N by simplifying both sides of the equation, then isolating the variable.

N=700

Hope this helps, if not, comment below please!!!

7 0
3 years ago
Read 2 more answers
Please help!!! 20 points
V125BC [204]

Answer:

A) x = (-8log(6)-2log(17))/(-2log(17)+log(6))

Step-by-step explanation:

Taking the logarithm of the equation, you have ...

(x+8)log(6) = (2x-2)log(17)

Subtracting the right side from the equation gives ...

x(log(6) -2log(17)) +8log(6)+2log(17) = 0

Subtracting the constant and dividing by the coefficient of x gives ...

x = -(8log(6) +2log(17))/(log(6) -2log(17)) . . . . . matches selection A

___

You don't need to work out the whole solution to determine the correct answer choice. Once you take the initial log, you find that the x-coefficient includes a multiplier of 2log(17). This term only appears in the denominator of choice A. (The value of x will be found after dividing by the x-coefficient, so you know this must show up in the denominator of the answer.)

6 0
3 years ago
Consider the following system of equations. -10x2-10y2=-300 5x2+5y2=150 Which statement describes why the system has infinite so
scoundrel [369]

Answer:

The equations represent circles that result in the same graph.

Step-by-step explanation:

we have

-10x^{2}-10y^{2}=-300

Divide by -10 both sides

x^{2}+y^{2}=30 -----> equation A

This is the equation of a circle centered at origin with radius r=\sqrt{30} \ units

and

5x^{2}+5y^{2}=150

Divide by 5 both sides

x^{2}+y^{2}=30 -----> equation B

This is the equation of a circle centered at origin with radius r=\sqrt{30} \ units

equation A and equation B are equal

therefore

The system has infinite solutions, because the equations represent circles that result in the same graph.

4 0
3 years ago
How do you solve these type of problems ?
-Dominant- [34]

Answer:

x = 15

Step-by-step explanation:

This involves the Secant and Segments Theorem.

8(19 + 8) = 9(9 + x)

216 = 81 + 9x

9x = 135

x = 15

8 0
2 years ago
What is the solution to the system of equations?
elixir [45]

Answer:

No solution

Step-by-step explanation:

-3x-4y-3z=-7\\2x-6y+2z=3\\5x-2y+5z=9\\\\

Lets consider the equation 2.

Here we multiply the LHS and RHS with (-1).

-3x-4y-3z=-7\\-(2x-6y+2z)=-3\\5x-2y+5z=9\\\\

Hence,

-3x-4y-3z=-7\\-2x+6y-2z=-3\\5x-2y+5z=9\\\\

When we add the equations we get,

0x+0y+0z=-10+9\\Hence,\\0=-1

As 0 doesn't equal to -1, answer is d) No solution

6 0
2 years ago
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