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Darina [25.2K]
3 years ago
6

How do you solve 5n + 3 + 4n = 30

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0
First you combine like terms. Adding 5n and 4n together to get 9n+3=30. Then you subtract 3 from 30 and end up with 9n=27.
Then you divide 27 by 9 and end up with n=3.
So the answer is 3.
maksim [4K]3 years ago
3 0
N=3
5n+3+4n=30 (add 5n and 4n)
9n+3=30 (Subtract 3 from both sides)
9n=27 (divide both sides by 9)
n=3
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If you flip a coin and roll a 6 sided dice what is the probability that you will flip a heads and roll a 5
Bogdan [553]

Answer:

1/12

Step-by-step explanation:

since there are 6 sides on a die, there is a 1/6 chance of any given number being rolled. And coins have a 1/2 chance of being heads.

1/2x1/6 = 1/12

4 0
3 years ago
Log3 a/3 = ??????????????????????????
Naddik [55]
We have that
<span>Log3 a/3
</span>Rewrite log3(a/3) using the change of base <span>formula

we know that
</span>The change of base rule can be used if a and b are greater than 0 and not equal to 1, and x is greater than 0<span>.
</span>so
loga(x)=<span>logb(x)/<span>logb<span>(a)
</span></span></span>Substitute in values for the variables in the change of base <span>formula
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in this problem
b=10
a=3
x=a/3

log3(a/3)=[log (a/3)]/[log (3)]

the answer is
[log (a/3)]/[log (3)]

8 0
3 years ago
Read 2 more answers
What is the rate of increase for the function f(x) = {(124)2X ?
Drupady [299]

Answer:

1/3

Step-by-step explanation:

7 0
3 years ago
Inverse of y=14x2 show derivations
Rudik [331]
<h2>Answer:</h2>

f^{-1}  (x)=\sqrt{\frac{x}{14}}.

<h2>Step-by-step explanation:</h2>

<h3>1. Write the expression.</h3>

y=14x^2

<h3>2. Substitute y for x, and x for y.</h3>

x=14y^{2}

<h3>3. Solve for y.</h3>

14y^{2}=x\\ \\y^{2} =\frac{x}{14} \\ \\y=\sqrt{\frac{x}{14}}

<h3>4. Express your result.</h3>

f^{-1}  (x)=\sqrt{\frac{x}{14}}.

4 0
1 year ago
The parabola with equation $y=ax^2+bx+c$ is graphed below:
Mashutka [201]

Answer:

m-n=2

Step-by-step explanation:

Instead of using the standard form, we can use the vertex form of a quadratic equation:

f(x)=a(x-h)^2+k

Where a is the leading coefficient, and (h, k) is our vertex.

Our vertex point is at (2, -4). So, let’s substitute 2 for h and -4 for k:

f(x)=a(x-2)^2-4

Now, we need to determine a.

We know that it passes through the point (4, 12). So, when x is 4, y must be 12. In other words:

12=a((4)-2)^2-4

Solve for a. Subtract within the parentheses:

12=a(2)^2-4

Add 4 to both sides:

16=a(2)^2

Square:

16=4a

Solve:

a=4

Thererfore, the value of a is 4.

So, our function is:

f(x)=4(x-2)^2-4

Now, let’s find our roots. Set the equation to 0 and solve for x:

0=4(x-2)^2-4

4=4(x-2)^2\\1=(x-2)^2\\x-2=\pm1 \\ x=2\pm1 \\ x=3\text{ or } 1

So, our roots are 1 and 3.

The greater root is 3 and the lesser root is 1.

Therefore, m-n, where m>n, is 3-1 or 2.

Our final answer is 2.

4 0
3 years ago
Read 2 more answers
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