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Darina [25.2K]
3 years ago
6

How do you solve 5n + 3 + 4n = 30

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0
First you combine like terms. Adding 5n and 4n together to get 9n+3=30. Then you subtract 3 from 30 and end up with 9n=27.
Then you divide 27 by 9 and end up with n=3.
So the answer is 3.
maksim [4K]3 years ago
3 0
N=3
5n+3+4n=30 (add 5n and 4n)
9n+3=30 (Subtract 3 from both sides)
9n=27 (divide both sides by 9)
n=3
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PLSSS ANSWER, 35 pointss
xxTIMURxx [149]

Answer:

1.

(y - 5)(x + y)

2.

{(x - y)}(x - y   + a)

3.

(b - 3)(5b - 17)

Step-by-step explanation:

1. The given polynomial is

x(y - 5) - y(5 - y)

We need to factor the second part to get:

x(y - 5)  +  y(y - 5)

We factor y-5 to obtain:

(y - 5)(x + y)

2. We have

{(x - y)}^{2}  - a(y - x)

We again factor -1 from the second part to get:

{(x - y)}^{2} +  a(x- y)

We now factor x-y to get:

{(x - y)}^{2}   + a(x- y)

{(x - y)}(x - y   + a)

3. We have

2(3 - b) + 5 {(b - 3})^{2}

We factor negative 1 from the first part to get

- 2(b - 3) + 5 {(b - 3})^{2}

We now factor b-3 to get:

(b - 3)( - 2 + 5(b - 3))

We now simplify to get:

(b - 3)( - 2 + 5b - 15) = (b - 3)(5b - 17)

4 0
3 years ago
(-5,-5); y = - 5x + 5
Phoenix [80]

Answer:

Step-by-step explanation:

5 0
3 years ago
The point (3, 4) is plotted on the coordinate plane below.
____ [38]

Answer:

D)  (-8, 3)

Step-by-step explanation:

90° counterclockwise brings point to (-4, 3)

translation 4 units to left brings point to (-8, 3)

5 0
3 years ago
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
4 years ago
What is the radical expression that is equivalent to the expression <br> (35) 1/4
LenKa [72]
Fourth root of 35. You take the denominator and make that the number above the root of sign and the numerator is how many times it is multiplied
5 0
3 years ago
Read 2 more answers
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