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3 years ago

Please help me out, please and thank you

Mathematics

1 answer:

Serhud [2]3 years ago

3 0

Well, a bisector is a ray that cuts the angle in half, which means that both of the angles are now the same. So, we get:
8x - 1 = 4x + 3
4x = 4
x = 1

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a room has a length of 11 ft if the room has an area of at least 133 ft what does the width of the room have to be at least

MissTica

Area is the length times the width.

When you know the area and one of the dimensions, divide the area by the known dimension to find the other one.

133 / 11 = 12.09

The room needs to be at least 12.09 feet wide. ( round answer if needed).

7 0

3 years ago

Help pls!!!!!!!!!!!!!!!!

BlackZzzverrR [31]

Answer:

b 3.13

Step-by-step explanation:

did this beofer

3 0

2 years ago

Read 2 more answers

Can someone help me with this question please?.

Taya2010 [7]

Answer: I think its n-12

3 0

3 years ago

Find the average value of the function on the given interval.<br> f(x)=ex/7; [0,7]

Anastaziya [24]

Answer:

$f_{avg}=e-1$

Step-by-step explanation:

We are given that a function

$f(x)=e^{\frac{x}{7}}$

We have to find the average value of function on the given interval [0,7]

Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{7-0}\int_{0}^{7}e^{\frac{x}{7}} dx$

$f_{avg}=\frac{1}{7}[e^{\frac{x}{7}}\times 7)]^{7}_{0}$

By using the formula

$\int e^{ax}=\frac{e^{ax}}{a}$

$f_{avg}=(e-e^0)=e-1$

Because $e^0=1$

$f_{avg}=e-1$

Hence, the average value of function on interval [0,7]

$f_{avg}=e-1$

8 0

3 years ago

Find the volume of the cone please help me

Ostrovityanka [42]

Here,

Height (h) = 5

Radius (r) = 5

Volume = ?

Now,

◆ Volume = 1/3πr²h

= 1/3*3.14*5*5*5

= 130.83 unit^3

I hope you understand...

It is Right answer...

Thank you♥♥

5 0

2 years ago

Please help me out, please and thank you​

Please help me out, please and thank you