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Vladimir79 [104]
3 years ago
13

Please help me out, please and thank you​

Mathematics
1 answer:
Serhud [2]3 years ago
3 0
Well, a bisector is a ray that cuts the angle in half, which means that both of the angles are now the same. So, we get:
8x - 1 = 4x + 3
4x = 4
x = 1
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Answer:

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Step-by-step explanation:

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2 years ago
The quality control manager of a chemical company randomly sampled twenty 100-pound bags of fertilizer to estimate the variance
lisabon 2012 [21]

Answer:

The 95% confidence interval for the variance in the pounds of impurities would be 3.829 \leq \sigma^2 \leq 14.121.

Step-by-step explanation:

1) Data given and notation

s^2 =6.62 represent the sample variance

s=2.573 represent the sample standard deviation

\bar x represent the sample mean

n=20 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,19)" "=CHISQ.INV(0.975,19)". so for this case the critical values are:

\chi^2_{\alpha/2}=32.852

\chi^2_{1- \alpha/2}=8.907

And replacing into the formula for the interval we got:

\frac{(19)(6.62)}{32.852} \leq \sigma^2 \frac{(19)(6.62)}{8.907}

3.829 \leq \sigma^2 \leq 14.121

So the 95% confidence interval for the variance in the pounds of impurities would be 3.829 \leq \sigma^2 \leq 14.121.

4 0
3 years ago
Help me plsss<br><br> And show identity. Thank you:)
zhuklara [117]

Answer:

see the formula in book

Step-by-step explanation:

change the first 2 brackets into cos sin like that

then after,change both into another formula

sin theta plus cos theta will come ans

4 0
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